answersLogoWhite

0


Best Answer

The perimeter is also twice as large.

User Avatar

Wiki User

10y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: When you enlarge the sides of a shape to twice their original size the perimeter of the enlargement is times as large as the perimeter of the original shape.?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Math & Arithmetic

What is the area and perimeter of a large square if two congruent rectangles are arranged so they from a square with each perimeter of rectangles is 36 inches?

area = 144 square units perimeter = 48 units


Does The perimeter of a polygon depends upon the number of sides of the polygon?

No, it does not. You can have a large triangle and a tiny quadrilateral. The first has fewer sides but its perimeter can be much much larger.


What is the perimeter of Minnesota in feet?

I highly doubt anyone knows. Perhaps, find a large map of Minnesota, estimate its perimeter (maybe by surrounding the border with string) then multiply by the proper scale factor.


Is it sometimes always or never true that the perimeter of a rectangle is numerically greater than its area?

Sometimes. Experiment with a small square and with a large square (though any shape rectangle will do). A square of 4 x 4 has a perimeter of 16, and an area of 16. A smaller square has more perimeter than area. A larger square has more area than perimeter.


Is there a relationship between the area and the perimeter of a rectangle?

No. Different rectangles, all with the same area, may have a different perimeter. Example:* A rectangle of 4 x 1 has an area of 4 square units, and a perimeter of 2(4+1) = 10. * A rectangle of 2 x 2 has an area of 4 square units, and a perimeter of 2(2+2) = 8. * A rectangle of 8 x 1/2 has an area of 4 square units, and a perimeter of 2(8 + 1/2) = 17. In fact, for any given area, you can make the perimeter arbitrarily large. On the other hand, you get the lowest perimeter if your rectangle is a square.