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Where are the points of contact made on the x and y axes when y equals 8x2 -26x plus 15?
Wiki User
∙ 6y ago
The x-axis is y = 0
→ y = 8x² - 26x + 15
→ 0 = 8x² - 26x + 15 = (4x - 3)(2x - 5)
So 4x - 3 = 0
→ 4x = 3
→ x = ¾ = 0.75
or 2x -5 = 0
→ 2x = 5
→ x = 2½ = 2.5
The y-axis is x = 0
→ y = 8x² - 26x + 15 = 8 × 0² - 26 × 0 + 15 = 15
→ The points of contact with the x- and y- axes of y = 8x² - 26x + 15 are:
(0.75, 0), (2.5, 0), (0, 15)
Wiki User
∙ 6y ago
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