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The two solutions are (x, y) = (-0.5, -sqrt(3.5)) and (-0.5, sqrt(3.5))

Q: Where are the points of contact when the line 2x plus 5 equals 4 crosses the curve y squared equals x plus 4 on the Cartesian plane?

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Points of intersection work out as: (3, 4) and (-1, -2)

If: y = x2-x-12 Then points of contact are at: (0, -12), (4, 0) and (-3, 0)

The vertex coordinate point of the vertex of the parabola y = 24-6x-3x^2 when plotted on the Cartesian plane is at (-1, 27) which can also be found by completing the square.

The number that equals 121 when squared is 11.

5.477225575 squared equals 30.

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It is the Cartesian equation of an ellipse.

Points of intersection work out as: (3, 4) and (-1, -2)

If: y = x2-x-12 Then points of contact are at: (0, -12), (4, 0) and (-3, 0)

It is (-0.3, 0.1)

Equations: y = x+4 and x^2 +y^2 -8x +4y = 30 The given equations will finally form a quadratic equation such as: x^2 +2x +1 = 0 Discriminant: 2^2 -4*(1*1) = 0 meaning there are equal roots Because the discriminant has equal roots the line is a tangent to the circle In fact the line makes contact with the circle at (-1, 3) on the Cartesian plane

5.477225575 squared equals 30.

The number that equals 121 when squared is 11.

The vertex coordinate point of the vertex of the parabola y = 24-6x-3x^2 when plotted on the Cartesian plane is at (-1, 27) which can also be found by completing the square.

b = sqrt32 or 4 root 2

No, it equals -2xy. lrn2math

It works out that line 3x-y = 5 makes contact with the curve 2x^2 +y^2 = 129 at (52/11, 101/11) and (-2, -11)

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