Wiki User
∙ 7y agoThe two solutions are (x, y) = (-0.5, -sqrt(3.5)) and (-0.5, sqrt(3.5))
Wiki User
∙ 7y agoPoints of intersection work out as: (3, 4) and (-1, -2)
If: y = x2-x-12 Then points of contact are at: (0, -12), (4, 0) and (-3, 0)
The vertex coordinate point of the vertex of the parabola y = 24-6x-3x^2 when plotted on the Cartesian plane is at (-1, 27) which can also be found by completing the square.
5.477225575 squared equals 30.
The number that equals 121 when squared is 11.
It is the Cartesian equation of an ellipse.
Points of intersection work out as: (3, 4) and (-1, -2)
If: y = x2-x-12 Then points of contact are at: (0, -12), (4, 0) and (-3, 0)
It is (-0.3, 0.1)
Equations: y = x+4 and x^2 +y^2 -8x +4y = 30 The given equations will finally form a quadratic equation such as: x^2 +2x +1 = 0 Discriminant: 2^2 -4*(1*1) = 0 meaning there are equal roots Because the discriminant has equal roots the line is a tangent to the circle In fact the line makes contact with the circle at (-1, 3) on the Cartesian plane
The vertex coordinate point of the vertex of the parabola y = 24-6x-3x^2 when plotted on the Cartesian plane is at (-1, 27) which can also be found by completing the square.
5.477225575 squared equals 30.
The number that equals 121 when squared is 11.
b = sqrt32 or 4 root 2
No, it equals -2xy. lrn2math
It works out that line 3x-y = 5 makes contact with the curve 2x^2 +y^2 = 129 at (52/11, 101/11) and (-2, -11)
This is a point on the cartesian coordinate plane... (10,13)