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Use this kinematic equation.

V^2 = Vo^2 + 2ay

Just initial velocity, so ( 0 velocity at paragee and - g constant-acceleration down )

Vo^2 + 2(-a)y = 0

- (Vo^2) = 2(-a)y

- (50 m/s^2) = 2(- 9.8 m/s^2)y

- 2500 = -19.6y

128 = y

128 meters high

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Q: Where is the arrow you shoot up at 50 meters per second when it runs out of speed?
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