Around the 81 in 1681.
If this value a satisfy the equation, then a is a solution for that equation. ( or we can say that for the value a the equation is true)
x2 = 49 Square root both sides to find the value of x:- x = 7
The square of any real number is non-negative. So no real number can have a negative square. Consequently, a negative number cannot have a real square root. If the discriminant is less than zero, the quadratic equation requires the square root of that negative value, which cannot be real and so must be imaginary.
If the side of the square is X then we are going to have 4x=x2 From this equation we get x=4
when you find the value, you SOLVED the equation. you CHECK the equation when you substitute the value in the variables place and check that the equation is true.
Such a value is said to be a solution, or a root, of the equation.
"430 5" is not an equation and it does not have an unknown value. So there can be no equation which has the same unknown value.
How is this different from determining if a value is a solution to an equation?
There is no possible value of x that will satisfy the given equation. There is no possible value of x that will satisfy the given equation. There is no possible value of x that will satisfy the given equation. There is no possible value of x that will satisfy the given equation.
Neither the 'x' nor the 'y' component should have any exponents (squared, cubed, square root, etc.) and therefore it should be a one-to-one ratio (each 'x' has one 'y' value and vice versa).
It depends on the equation.
That depends on what the equation is.