All numbers divisible by 90 are also divisible by 9 and 10
No, a number can only be divisible by a number smaller than it
There is no 4-digit number that is divisible by 2356 and 10.
A four-digit number that meets these criteria is 1080. It is an even number (divisible by 2), divisible by 9 (1080 ÷ 9 = 120), divisible by 10 (1080 ÷ 10 = 108), and divisible by 3 (1080 ÷ 3 = 360). However, it is also divisible by 3, so it does not satisfy your request for a number that is not divisible by 3. Instead, a correct example is 1086, which is even and divisible by 9 (1086 ÷ 9 = 120.67) but not by 3. Hence, no valid 4-digit number meets all criteria simultaneously.
If a number is divisible by 10 it cannot give any remainder other than 0. That is what "divisible by" means!
The smallest number which is exactly divisible by the numbers 8 9 and 10 is 360.
To determine if 235 is divisible by 9, we sum its digits: 2 + 3 + 5 = 10. Since 10 is not divisible by 9, 235 is not divisible by 9. In order for a number to be divisible by 9, the sum of its digits must be divisible by 9.
445 is divisible by 5 because 445 is a multiple of 5. 445 is not divisible by 9 or 10 because 445 is not a multiple of 9 or 10. 445 is not divisible by 5910 because it is impossible for a number to be divisible by a greater number.
LCM(6, 9, 10) = 90
9000
90
There are no numbers that satisfy this. If a number is divisible by both 2 and 5, then it must also be divisible by 10.
Your question is impossible to answer. Any number that is divisible by both 2 and 5 will also be divisible by 10. 30 and 60 are not divisible by 9.