Let the numbers be 'm' & 'n'
Hence
m + n = 2
mn = - 280
It follows that m = 2 - n
Substitute
(2 - n)n = -280
Multiply out the brackets
2n - n^2 = -280
n^2 - 2n - 280 = 0
It is now in Quadratic form. Either use the Quadratic Eq'n or 'Complete the Square'.
n^2 - 2n = 280
(n - 1)^2 - (-1)^2 = 280
(n - 1)^2 = 281
Square root both sides
n -1= sqrt(281)
n = 1 +/- sqrt(281)
-46
-5 and -8
221
That depends what you mean with "and": whether you want to add the numbers, multiply them, etc.That depends what you mean with "and": whether you want to add the numbers, multiply them, etc.That depends what you mean with "and": whether you want to add the numbers, multiply them, etc.That depends what you mean with "and": whether you want to add the numbers, multiply them, etc.
323
If you multiply 4 by 58 and add 48, the answer is 280.
The two numbers that multiply to -72 and add to -29 are approximately 3.57 and -32.57.
To solve this problem, we are looking for two numbers that multiply to 150 and add to -19. Let’s break it down: Product of the two numbers: The two numbers should multiply to give 150. Sum of the two numbers: The same two numbers should add up to -19.
307
start with 0,1 add together =1 add to sequence, gives 0,1,1 add last two numbers =2 add to sequence, gives 0,1,1,2 add last two numbers =3 add to sequence, gives 0,1,1,2,3 add last two numbers = 5 add to sequence, gives 0,1,1,2,3,5 repeat forever, list is endless
Product = multiply.
There are infinitely many pairs of numbers that will add to 105.8 and infinitely many pairs of numbers that will multiply to 105.8 but there are no pair that will add AND multiply. I do not think there are larger sets, but I could be wrong. One example of a triplet adding and multiplying to the same number is 1, 2 and 3. They add to 6 and multiply to 6.