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Let the numbers be 'm' & 'n'

Hence

m + n = 2

mn = - 280

It follows that m = 2 - n

Substitute

(2 - n)n = -280

Multiply out the brackets

2n - n^2 = -280

n^2 - 2n - 280 = 0

It is now in Quadratic form. Either use the Quadratic Eq'n or 'Complete the Square'.

n^2 - 2n = 280

(n - 1)^2 - (-1)^2 = 280

(n - 1)^2 = 281

Square root both sides

n -1= sqrt(281)

n = 1 +/- sqrt(281)

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lenpollock

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โˆ™ 2022-11-27 19:40:47
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A polynomial of degree zero is a constant term

The grouping method of factoring can still be used when only some of the terms share a common factor A True B False

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Q: Which two numbers will add up to 2 and when multiply gives us -280?
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