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We're not qualified to deal with the hydraulics of the situation. We're not even sure

that there's enough information given regarding the depth of the well, the size of

the pipe, etc., since you don't indicate the flow rate, i.e. how much water you want

in how much time.

But you do mention a 25hp motor, and we know how to handle that.

1 hp = 746 watts.

25hp = 18.65 KW.

To run the pump at max capacity of 25hp, you need to supply it with 18.65 KW of

electric power. If it's an AC motor, you also have to account for the power you'll

lose in the process of converting the DC from the solar cells to AC for the motor.

18 KW sounds to us like an awful lot to plan on getting out of any solar array

with a reasonable size and reasonable price.

Q: Which capacity of solar cells will be required to run 25 hp electric motor for pumping water from 350 ft deep tube well size of pipe inside the well is 5 inches and outer size of the pipe is 6 inch?

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360 inches are required for a first down

It is 120 cubic inches: not more, nor less.

Capacity means volume, and volume is equal to L x W x H. 5 x 5 x 2= 50 cubic inches

None but the cubic capacity of the hole is 16 cubic inches

27 liters means it has a capacity of about 1,647.6 cubic inches.

54in

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