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A circle with centre (x0, y0) and radius r has the equation of:

(x -x0)² + (y - y0)² = r²

By writing the equation of any circle in this form its centre and radius can be determined.

To completely lie within a quadrant, the centre of the circle must be more than r away from the y- and x-axes:

  • In the first quadrant if: x0 > r and y0 > r
  • In the second quadrant if: x0 < -r and y0 > r
  • In the third quadrant if: x0 < -r and y0 < -r
  • In the fourth quadrant if: x0 > r and y0 < -r

If either x0 or y0 (or both) is exactly r away from the y- or x-axis then the circle is on boundary between quadrants, and if either x0 or y0 (or both) is less than r away from the y- or x-axis, then the circle is in more than one boundary.

f x0 < r from the y-axis then the circle is in quadrants I and II, or y0 < r from the x-axis then the circle is in quadrants III and IV; if both less than r away from their respective axes, the the circle is in all four quadrants.

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Q: Which circles lie completely within the fourth quadrant?
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A circle with 5 circles within it...that's the symbol for it


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Hey, this one is nice! I will venture the following: * 3: make them tangent in one point, with no intersection * 2: make them have a small intersection, ie. crossing in two points * 1: make them tangent from the inside * 0: make one fall completely within the other Giving the explanation would just be killing the imagination.


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How do you find the venn diagram for union of three sets?

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