The answer will depend on the configuration of the circles: they could overlap only pairwise - a bit like the Olympic rings, or they could have regions where several circles overlap.
One configuration could be as follows. In order to visualize the circles, draw them yourself, following these instructions carefully:-
Draw your first circle, maybe about 8cm in diameter. Write '5' in the center.
Draw another circle to the left, with its center about 0.5 cms inside the circumference of the 1st circle, ensuring that the '5' is within this second circle. Write a small '1' just right of center of this second circle, and '9' in the open space of this second circle, i.e. to the far left.
Draw a lower circle in the same way, with its center about 0.5 cm up from the circumference of the 1st circle, ensuring that the '5' is within this third circle. Write a small '4' just above center of this third circle, and '6' in the open space of this third circle, i.e. at the bottom.
Draw a circle to the right in the same way, with its center about 0.5 cm in from the circumference of the 1st circle, ensuring that the '5' is also within this fourth circle. Write a small '3' just left of center of this fourth circle, and '7' in the open space of this fourth circle, to the far right.
Finally, draw an upper circle, with its center about 0.5 cm down from the circumference of the 1st circle, ensuring that the central '5' is also within this fifth circle. Write a small '2' just below center of this fifth circle, and write '8' in the above open space of this circle.
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You will have five circles and will have used each number 1 to 9 only once, each within its own space.
Your central circle will have 5,1,4,3,2 (total 15) within its boundaries.
The left circle will have 9,1,5 (total 15) within its boundaries.
The bottom circle will have 5,4,6 (total 15) within its boundaries.
The right circle will have 5,3,7 (total 15) within its boundaries.
The top circle will have 8,2,5 (total 15) within its boundaries.
And all the requirements of this puzzle are fulfilled.
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A Venn diagram for numbers divisible by both 4 and 5 would have two overlapping circles. One circle would represent numbers divisible by 4, while the other circle would represent numbers divisible by 5. The overlapping region where the two circles intersect would represent numbers divisible by both 4 and 5. This intersection would include numbers that are multiples of both 4 and 5, such as 20, 40, 60, and so on.
Circle is a shape. We have gotten to know a lot from circles. Because of circles, we get PI, radius, diameter, circumference, and other things. Circles fall into geometry, which is math. We can make many mathematical equations from circles.
Yes, it can as long as it is not the tangent line of the outermost circle. If it is tangent to any of the inner circles it will always cross the outer circles at two points--so it is their secant line--whereas the tangent of the outermost circle is secant to no circle because there are no more circles beyond that last one.
The Venn diagram consists of a rectangle with two concentric circles. In the inner circle are the multiples of 8. In the outer circle are multiples of 4 which are not also multiples of 8. That is, they are 4 times all odd numbers. Mathematically, that is the set of numbers 4*(2n-1) where n is an integer. Outside the circles, are all the integers that are not divisible by 4.
Draw your Venn Diagram as three overlapping circles. Each circle is a set. The union of the sets is what's contained within all 3 circles, making sure not to count the overlapping portion twice. An easier problem is when you have 2 sets, lets say A and B. In a Venn Diagram that looks like 2 overlapping circles. A union B = A + B - (A intersect B) A intersect B is the region that both circles have in common. You subtract that because it has already been included when you added circle A, so you don't want to add that Again with circle B, thus you subtract after adding B. With three sets, A, B, C A union B union C = A + B - (A intersect B) + C - (A intersect C) - (B intersect C) + (A intersect B intersect C) You have to add the middle region (A intersect B intersect C) back because when you subtract A intersect C and B intersect C you are actually subtracting the very middle region Twice, and that's not accurate. This would be easier to explain if we could actually draw circles.
Do a prime factorization of each number. Draw 3 overlapping circles. Place the factors into each circle: note: some will go into the overlapping sections of the circles. All those numbers in the overlapping section of ALL circles will form the GCF. Multiply those in that overlapping section and that equals the GCF.
A Venn diagram for numbers divisible by both 4 and 5 would have two overlapping circles. One circle would represent numbers divisible by 4, while the other circle would represent numbers divisible by 5. The overlapping region where the two circles intersect would represent numbers divisible by both 4 and 5. This intersection would include numbers that are multiples of both 4 and 5, such as 20, 40, 60, and so on.
A picture with two circles overlapping can represent concurrent powers. Picture a red circle and a blue circle overlapping; the purple section represents concurrent powers.
A Venn Diagram consists of two overlapping circles. Each circle includes information about an item or topic. The overlapping portion includes information that the two have in common.
A Venn diagram involves two overlapping circles. In one circle, write a subject and all the related ideas to that subject. Do the same thing in the other circle. Then, where the circles overlap, write what the two subjects have in common.
A Venn diagram has overlapping circles to help visualize the similarities and differences between two or more characters or subjects. Each circle represents a different character or subject, and the overlapping area shows what they have in common.
Circles and spheres both have infinite numbers of lines of symmetry
The c starts with the ball in the circle on the court. They are allowed anywhere except the semi circles.(Ds)
If you were to find the GCF of 20 and 36. Draw 2 overlapping circles. List "20" above one of the circles and "36" above the other. In the circle under "20", list the factors of 20 that are NOT factors of 36- 1, 5, 10, 20. In the other circle, list the factors of 36 that are NOT factors of 20- 1, 3, 6, 9, 12, 36. The factors that 20 and 36 that are in common are listed in the overlapping part of the circle or intersection- 2, 4. The greatest number in common is 4 (GCF). In other words, the largest number listed in the intersection is the GCF.
1^2 or 2^2 or 3^2 or 4^2.... and it goes on...where diameter of circle is equal to the side of square divided by square root of total numbers of circles.. eg : side of square = 10 no of circles = 2^2 square root = 2 therefore diameter = 10/2=5.
Circle A only: 9, 27, 45, 63, 81, 99, 117 Circle B only: No numbers Circle C only: 21, 42, 84, 105 Circles A and B intersect: 18, 36, 54, 72, 90, 108 Circles B and C intersect: No numbers. Circles A and C intersect: 63 Circles A, B and C intersect: 126
a circle