If the original number was even, the ones place will be zero; otherwise it will be 5.
0 or 5
If the digits go from the thousands place to the ones place then we need to use 4 digits. Because the digits are all even, we are forced to use the 4 even digits (2, 4, 6 and 8). As they decrease by 2 each time, the only option for ordering them is greatest to lowest. Therefore, the number described in the question is 8,642.
Counting digits: 0 Number of "things" in the ones place: 6 Total "things": 236
the 3 digits is the ones place the 5 digits is the tenths place the 9 digits is the hundredths place
Significant digits refer to the number of digits that are known versus the number of digits that are estimated. So if the number 20 is an approximation, there is only one significant digit, which is the 2. However, if 20 is accurate to the ones place, then there are 2 significant digits. 20.00 has four significant digits, because it is known that the number is accurate down to the hundredths place.
A single digit in a number can have a place value. A number with several digits cannot.
38977 is in ones place9 is in tens place (and is three times the number in thousands place)8 is in the hundreds place3 is in the thousands place7+9+8+3=27
They are equal to whatever they are equal to.
No. It has four digits and each one of these is in a different place. No. It has four digits and each one of these is in a different place. No. It has four digits and each one of these is in a different place. No. It has four digits and each one of these is in a different place.
Answer: 2058 Explanation: Consider the thousandths place. You can place digits 1,2,3,4,5,6 (not 0 as the number would then become a 3-digit). Now consider hundredths place. You can place all the allowed digits ( ie, 0,1,2,3,4,5,6). In the same way you can place all allowed digits in tens and ones place. No. of digits which can be placed in thousandths place: 6 No. of digits which can be placed in hundredths place: 7 No. of digits which can be placed in tens place: 7 No. of digits which can be placed in ones place: 7 Total possible numbers which can be formed: 6 X 7 X 7 X 7 = 2058
The "ones" place is always the last digit in any number so multiples of 5 always have either 5 or 0 (zero) in the "ones" digit position.
Fives and zeros