If the original number was even, the ones place will be zero; otherwise it will be 5.
Counting digits: 0 Number of "things" in the ones place: 6 Total "things": 236
10864
The product of 39 multiplied by 39 is 1521. This can be calculated by multiplying the tens place of each number (3 x 3 = 9) to get the hundreds place of the result, and then multiplying each number by the other number's digits and adding them together (3 x 9 = 27) to get the tens and ones place of the result. Therefore, 39 x 39 = 1521.
415
The "ones" place is always the last digit in any number so multiples of 5 always have either 5 or 0 (zero) in the "ones" digit position.
If the digits go from the thousands place to the ones place then we need to use 4 digits. Because the digits are all even, we are forced to use the 4 even digits (2, 4, 6 and 8). As they decrease by 2 each time, the only option for ordering them is greatest to lowest. Therefore, the number described in the question is 8,642.
0 or 5
86,420
2,4,6,8,and 0 are divisible by 2 in the ones digit. Zero is only divisible in a number with 2 digits or more. 0 itself is not divisible by 2.
Counting digits: 0 Number of "things" in the ones place: 6 Total "things": 236
63
10864
the 3 digits is the ones place the 5 digits is the tenths place the 9 digits is the hundredths place
50401
86420
There are 5 digits in the number 67392. Each digit represents a place value in the number, with the leftmost digit being the ten-thousands place and the rightmost digit being the ones place. In this case, the digits are 6, 7, 3, 9, and 2.
38977 is in ones place9 is in tens place (and is three times the number in thousands place)8 is in the hundreds place3 is in the thousands place7+9+8+3=27