81 and 121 are two examples out of many more
The square root of an even number can be an even number (if it is a perfect square), or an irrational number (if it is not).
Assuming you know that your number is a perfect square, the square root of an even number is even, and the square root of an odd number is odd.
no
The square root of 200 is not a whole number, and therefore can neither be classified as odd or even.
If you mean square root when you say 'root'then... Yes, only the same number can be a square root and the factors of an even number must contain at least one even number So, if one of the roots is even then the other is the same number and is therefore even.
No, it is not even a real number. The square root of negative 5 is the square root of 5, times i.
Only whole numbers are even or odd, and the square root of 75 is not a whole number.
No. 3 is not a perfect square, so its square root is irrational.
No, it may be not even a rational number. Square root of 2 is 1,414213562... for example.
I cannot see how odd or even will determine the number of digits in the square root. For example:100 is an even number, and its square root is 10 (2 digits)121 is an odd number, and its square root is 11 (2 digits)Maybe the question is not phrased properly for what the questioner is asking.
No. The square root of -24 isn't even real, let alone rational because the square root of any negative number is going to be an imaginary number.
Well . . there is not even such a thing as the square root of -6, unless you are working with non-real numbers. The square root of + 6, though, is not a whole number.