Q: Which has an odd sum 9 plus 9 5 plus 3 6 plus 7 2 plus 8?

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2 + 3 = 5 Two plus any odd prime number is odd.

That isn't possible. The sum of three odd numbers will always be odd. You can make the sum of 3 prime numbers equal to 32 if one of them is 2 (which is not odd).

The prime numbers 3 an 7 are both odd and sum to 10.

#include<stdio.h>int main () { int sum = 0; for (int odd=3; odd<100; odd+=2) { printf ("%d\n", odd); sum += odd; } printf ("\nSum = %d\n", sum); return 0; }

Impossible. They are all odd numbers. The sum of 5 odd numbers is also an odd number and cannot therefore total 50.

No, the sum of three odd numbers will always be odd.

When the sum of a number plus 3 is squared, it is 11 more than the sum of the number plus 2 when squared.

The sum of a number plus 3 to the square root of 9 to the sum of 2 would equal -2. This is a math problem.

False. The sum of 3 and 3 is 6. And 6 is even. The product of two odd numbers is always odd. false the sum of 2 odd numbers is always even 3+3=6 5+5=10 103+103=206

Print "Type the upper limit (n) ?" Input n K = -1 WHILE K < = n K = K + 2 Sum = Sum + K WEND Print "The sum of all odd numbers up to "; n; "is "; Sum

Answer is 4000000: The sum of the first N odd numbers is N^2. Look at 1,3,5 for example. There are 3 numbers and the sum is 9 which is 3^2. Add 7 and the sum is 16 which is 4^2. So the of the first 2000 consecutive odd numbers is 2000^2 Note 2000 is 2(10^3). When we square that it is 4x10^6=4000000

Lets find out.2 + 3 = 5 (Odd)4 + 7 = 11 (Odd)12 + 13 = 25 (Odd)So it appears that the sum of an even and odd number is an odd number.

if it is not this . -3<x<-2 < or equal

Yes it does, since 1 (an odd whole number) plus another 1 equals 2 (an even whole number). So only 2 plus an odd whole number equals a consecutive odd whole number. 1 plus 2 equals 3. 3 plus 2 equals 5. And so on.

Some odd numbers can be written as the sum of prime numbers. 2 + 3 = 5

Assuming the series is 1 + 3 + 5 + ... + 25, the answer is 169.

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Let's talk this out and see if we can work it out. The sum of the first N odd integers means, 1+3+5+7+9+11+... Where N is how many odd numbers we're adding. Let's choose numbers for N, and see if we can find a pattern. N=1 --> 1 (sum of the first odd integer) N=2 --> 1 + 3 = 4 (sum of the first 2 odd integers) N=3 --> 1 + 3 + 5 = 9 (sum of the first 3 odd integers) N=4 --> 1 + 3 + 5 + 7 = 16 Do you notice a pattern yet? Take a look at when N = 2, what is the sum? That's right, 4! and when N = 3... the sum is 9. N = 4 the sum is 16.... I see a pattern, do you? Answer: If you don't, you'll notice that the sum of the first N odd integers is always = N2

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It may or it may not. Parity (whether the number is odd or even) has nothing to do with a sum of two odds being positive or negative. -5 + 3 = -2 is negative, while 5 + 3 = 8 is positive.

87

Sum = 79*(79+1)/2 = 79*80/2 = 3160