6 plus 7
2 + 3 = 5 Two plus any odd prime number is odd.
That isn't possible. The sum of three odd numbers will always be odd. You can make the sum of 3 prime numbers equal to 32 if one of them is 2 (which is not odd).
The prime numbers 3 an 7 are both odd and sum to 10.
Since 270 is an even number, then three consecutive odd numbers cannot add to 270. ,because Odd + odd = even (2 numbers_ Even + odd = odd ( plus a third number) odd + odd = even (plus a fourth number) even + odd = odd (plus a fifth number) Notice from the table that the third odd number gives an odd answer; not an even answer. e.g. three odd numbers 3,5, & 7. 3 + 5 = 8 (even) 8 + 7 = 15 ( odd) et. seq.,
Impossible. They are all odd numbers. The sum of 5 odd numbers is also an odd number and cannot therefore total 50.
Print "Type the upper limit (n) ?" Input n K = -1 WHILE K < = n K = K + 2 Sum = Sum + K WEND Print "The sum of all odd numbers up to "; n; "is "; Sum
False. The sum of 3 and 3 is 6. And 6 is even. The product of two odd numbers is always odd. false the sum of 2 odd numbers is always even 3+3=6 5+5=10 103+103=206
No, the sum of three odd numbers will always be odd.
When the sum of a number plus 3 is squared, it is 11 more than the sum of the number plus 2 when squared.
The sum of a number plus 3 to the square root of 9 to the sum of 2 would equal -2. This is a math problem.
Answer is 4000000: The sum of the first N odd numbers is N^2. Look at 1,3,5 for example. There are 3 numbers and the sum is 9 which is 3^2. Add 7 and the sum is 16 which is 4^2. So the of the first 2000 consecutive odd numbers is 2000^2 Note 2000 is 2(10^3). When we square that it is 4x10^6=4000000
Lets find out.2 + 3 = 5 (Odd)4 + 7 = 11 (Odd)12 + 13 = 25 (Odd)So it appears that the sum of an even and odd number is an odd number.