Best Answer

The largest 3 digit number which when divided by 69 and 12 to give a remainder of 1 is 829.

What we want is one more than a common multiple of 69 and 12.

The common multiples of 69 and 12 are the multiples of their least common multiple:

69 = 3 x 23

12 = 2^2 x 3

→ lcm = 2^2 x 3 x 23 = 276

The largest multiple of 276 which is a 3 digit number:

999 ÷ 276 = 3 r 171 → largest 3 digit multiple of 276 is 3 × 276 = 828

→ the required number is 828 + 1 = 829.

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Q: Which is the greatest number of 3 digit which when divided by 69 and 12 leave a remainder of 1?

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Every 2 digit number, when divided by the number one less than it, will result in a remainder of 1.

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A multiple is a number that may be divided by another number with no remainder. Therefore, 90 is the largest two-digit multiple of 10, because 10x9 = 90, or 90 divided by 10 =9.

This is impossible. A two digit number n divided by 345 has a remainder equal to n. If you meant to say divided by 3,4,5 or 6 then the answer is 62.

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The process of multiplication doesn't produce remainders.The process of division does.If you want to divide a 3-digit number by a one-digit numberand get a remainder of 8, try these:107 divided by 9116 divided by 9125 divided by 9134 divided by 9143 divided by 9..Add as many 9s to 107 as you want to, and then divide the result by 9.The remainder will always be 8.

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