You can't have a remainder of 6 when you divide by 2! JHC!
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14. The largest possible number for a remainder is 1 less than the divisor.
To find the number, multiply the divisor and quotient, then add the remainder. 9 (divisor) times 6 is 54. 54 plus 7 is 61. The number is 61.
95 divided by 10
2
The largest 2-digit number is 99. When 99 is divided by 4, the quotient is 24 with a remainder of 3. This is because 99 divided by 4 equals 24 with a remainder of 3.
0.2667
divided a number by 8. His quotient was 73. The remainder was6. What was the number?
810: quotient 1, remainder 1
Quotient 0, remainder 805. Note that you will always get this pattern when you divide a smaller number by a larger one - i.e., the quotient will be zero, and the remainder will be the dividend.
154
44
The divisor is divided into the dividend producing a quotient and no remainder.
To find the number that gives a quotient of 5 and a remainder of 3 when divided by 7, we can use the formula: ( \text{number} = \text{divisor} \times \text{quotient} + \text{remainder} ). Here, the divisor is 7, the quotient is 5, and the remainder is 3. So, the calculation is ( 7 \times 5 + 3 = 35 + 3 = 38 ). Therefore, the number is 38.
When 25 is divided by 9, the quotient is 2 with a remainder of 7. This can be calculated by dividing 25 by 9, which equals 2 with a remainder of 7. The quotient represents the whole number of times 9 can be divided into 25, and the remainder is what is left over after dividing as many whole times as possible.
200
53