The factors are 1, 7 and 49. The multiples are 0, 49, 98, 147, 196 ... (just keep adding 49)
No, the only factors of 49 are 1, 7, and 49. Therefore, 8 and 5 are not factors of 49.
They are 1*49=49 and 7*7=49
The factors of 7 are 1 and 7. Neither of them are multiples of 42. Put the other way, 7, 14, 21 and 42 are multiples of 7 that are factors of 42.
A common factor is '7' 3 x 7 = 21 7 x 7 = 49 '7' appears in both multiples.
49 is a composite number because it has factors other than 1 and itself. It is not a prime number. The 3 factors of 49 are 1, 7, and 49. It is square number, 72, so it has an odd number of factors. The factor pairs of 49 are 1 x 49 and 7 x 7. The proper factors of 49 are 1 and 7 or, if the definition you are using excludes 1, the only one is 7. The prime factors of 49 are 7 and 7. Note: There is repetition of these factors, so if the prime factors are being listed instead of the prime factorization, usually only the distinct prime factors are listed. The only distinct prime factor (listing each prime factor only once) of 49 is 7. The prime factorization of 49 is 7 x 7 or, in exponential form, 72. NOTE: There cannot be common factors, a greatest common factor, or a least common multiple because "common" refers to factors or multiples that two or more numbers have in common. A factor tree: 49 7, 7 So, the prime factorization is 7 x 7.
The multiples are as follows:49,56,63,70,77,84
well its pretty simple i think there are only 3 factors 7,1,49
The common factors of 7 and 49 are 1 and 7.
The factors of 49 are: 1 7 49. The prime factors are: 7 x 7
The factors of 49 are: 1 7 49 The prime factors are: 7 x 7
The factors of 49 are 1, 7, and 49.