9000 is one.
9000 is one such number.
2520
There are infinitely many numbers divisible by 2, 3, 5 and 9. One such is 900.
The answer is 135. 15 times 9 equals 135 27 times 5 equals 135
yes it is because 90 has a 0 at the end if the end of the number is 0 or 5 it is divisble by 5
They are divisble by 5 because every number at the end if it ends in 0 or 5 then its divisble by 5.
yes for a number to be divisble by 3 you have to add the numbers together and see if you can divide it by 3 evenly 1+5+3= 9 9 can be divided by 3 evenly so that makes the number, 153 divisble by 3
Any of its multiples
It is: 405/5 = 81
any number evenly divisble if it ends in 0 or 5
any number is divisible by another.. 7960/9=884.4444 not evenly divisble but divisible one quick way /math trick to know if a number is evenly divisble by 9 is add the integers in this case 7+9+6=22 2+2=4 so not evenly divisble by 9 however 180 1+8 is divisble by 9 171 (1+7+1) is evenly divisble by 9 171/9=19 13464 ==> 1+3+4+6+4=18 1+8=9 so evenly divisble by 9 13464/9=1496
Any whole number ending in 5 or 0