Any multiple of 30.
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∙ 8y agoThe number 90 is divisible by both 2 and 3.
No,because 45 is not divisible by both 2 and 3. In order for a number to be divisible by 6 it has to be divisible by both 2 and 3.
the number that is divisible by two and three is six
Rule: If it is divisible by 2 and by 3Numbers are divisible by 6 if they are divisible by 3 and 2. Therefore, for example, since 18 is divisible by 3 and 2, it is also divisible by 6.The divisibility rule for 6 is, it can go into the number if 2 and 3 can also.
Something divisible by 6 has to be divisible by both 2 and 3. and that just answers that anything disible by 6 is divisible by 2
Any number that is divisible by both 2 and 3 is divisible by 6.
Since 5232 is divisible by both 2 and 3, it is divisible by 6.A number must be divisible by both 2 and 3 to be divisible by 6.The number 5232 is even, so it is divisible by 2.If you add the individual digits in the number (5+2+3+2=12) you get a number that is divisible by 3, meaning the original number (5232) is also divisible by 3.
The number 90 is divisible by both 2 and 3.
No,because 45 is not divisible by both 2 and 3. In order for a number to be divisible by 6 it has to be divisible by both 2 and 3.
It is not divisible by 6. Note:If a number id divisible by 6 then it must be divisible by both 2 and 3.The above number is not divisible by 2 and 3 either.
To determine if a number is divisible by 6, it must be divisible by both 2 and 3. To determine if a number is divisible by 2, it should be even - in other words, it should end with 0, 2, 4, 6, or 8. To determine if a number is divisible by 3, the sum of its digits should be divisible by 3. 54,132 is an even number, so it is divisible by 2. 5 + 4 + 1 + 3 + 2 = 15, which is divisible by 3, so 54,132 is divisible by 3. Since 54,132 is divisible by both 2 and 3, it is divisible by 6.
the number that is divisible by two and three is six
72 is.
These numbers are not evenly divisible by 6: Any number smaller than 6. Any odd number (not divisible by 2). Any number not divisible by 3. If a number is divisible by both 2 and 3, it is divisible by 6.
Rule: If it is divisible by 2 and by 3Numbers are divisible by 6 if they are divisible by 3 and 2. Therefore, for example, since 18 is divisible by 3 and 2, it is also divisible by 6.The divisibility rule for 6 is, it can go into the number if 2 and 3 can also.
Something divisible by 6 has to be divisible by both 2 and 3. and that just answers that anything disible by 6 is divisible by 2
102 is divisible by: 1 2 3 6 17 34 51 102.