Something divisible by 6 has to be divisible by both 2 and 3. and that just answers that anything disible by 6 is divisible by 2
This statement is false. A number can be divisible by 3 and still be even, such as the number 6, which is both divisible by 3 and an even number. Divisibility by 3 is determined by the sum of a number's digits, not by whether the number is odd or even. Therefore, being divisible by 3 does not imply that a number must be odd.
If a number is divisible by both 8 and 11, it will be divisible by 88.
If a number is divisible by both 2 and 3, it is also divisible by 6. This is because 6 is the least common multiple of 2 and 3. Therefore, any number that meets the criteria of being divisible by both 2 and 3 will also be divisible by 6.
A number is divisible by 36 if it is divisible by both 4 and 9. For a number to be divisible by 4, its last two digits must form a number that is divisible by 4. For divisibility by 9, the sum of its digits must be divisible by 9. If a number meets both of these criteria, it is divisible by 36.
No,because 45 is not divisible by both 2 and 3. In order for a number to be divisible by 6 it has to be divisible by both 2 and 3.
Quickly check to see whether it's divisible by both 2 and 3. Here's how to do that easily: -- The number is divisible by 2 if it's an even number . . . the last digit is 2, 4, 6, 8, or 0. -- The number is divisible by 3 if the sum of its digits is divisible by 3.
This statement is false. A number can be divisible by 3 and still be even, such as the number 6, which is both divisible by 3 and an even number. Divisibility by 3 is determined by the sum of a number's digits, not by whether the number is odd or even. Therefore, being divisible by 3 does not imply that a number must be odd.
Any number that is divisible by both 2 and 3 is divisible by 6.
If a number is divisible by both 8 and 11, it will be divisible by 88.
If a number is divisible by both 2 and 3, it is also divisible by 6. This is because 6 is the least common multiple of 2 and 3. Therefore, any number that meets the criteria of being divisible by both 2 and 3 will also be divisible by 6.
The smallest number that is divisible by both 34 and 35 is 1,190.
A number is divisible by 36 if it is divisible by both 4 and 9. For a number to be divisible by 4, its last two digits must form a number that is divisible by 4. For divisibility by 9, the sum of its digits must be divisible by 9. If a number meets both of these criteria, it is divisible by 36.
No,because 45 is not divisible by both 2 and 3. In order for a number to be divisible by 6 it has to be divisible by both 2 and 3.
Since 5232 is divisible by both 2 and 3, it is divisible by 6.A number must be divisible by both 2 and 3 to be divisible by 6.The number 5232 is even, so it is divisible by 2.If you add the individual digits in the number (5+2+3+2=12) you get a number that is divisible by 3, meaning the original number (5232) is also divisible by 3.
a number is divisible by 12 if the number is also divisible by both 3 and 7. You mean a number is divisible by 21 if it is divisible by 3 and 7.
Every number is divisible by any non-zero number. Furthermore, 4770 is evenly divisible by both 3 and 9.
A number is divisible by 10 if its last digit is 0. To determine if a number is divisible by 235, it must be divisible by both 5 and 47 (since 235 = 5 × 47). Therefore, for a number to be divisible by both 235 and 10, it must end in 0 (for divisibility by 10) and be divisible by 47.