LCM(2, 3, 7) = 42
All multiples of 6 Numbers are evenly divisible by 6 if they are evenly divisible by both 2 AND 3. Even numbers are always evenly divisible by 2. Numbers are evenly divisible by 3 if the sum of all the individual digits is evenly divisible by 3. For example, the sum of the digits for the number 3627 is 18, which is evenly divisible by 3 but 3627 is an odd number so the number 3627 is not evenly divisible by 6
1, 2 and 3
2 is a prime number. It is only evenly divisible by itself and one.3 is a prime number. It is only evenly divisible by itself and one.
All multiples of 6 Numbers are evenly divisible by 6 if they are evenly divisible by both 2 AND 3. Even numbers are always evenly divisible by 2. Numbers are evenly divisible by 3 if the sum of all the individual digits is evenly divisible by 3. For example, the sum of the digits for the number 3627 is 18, which is evenly divisible by 3 but 3627 is an odd number so the number 3627 is not evenly divisible by 6
If the sum of the digits equals 3, the number is evenly divisible by 3. 2 + 0 + 1 = 3, so 201 is evenly divisible by 3. 1, 3, 67, 201
No, 6 does not go evenly into 2345. A method to find out if something is divisible by 6 is... Is it divisible by 2? Is it divisible by 3? 2*3=6 So, 2 and 3 should be able to go evenly into the number.
2 is a prime number. It is only evenly divisible by itself and one.3 is a prime number. It is only evenly divisible by itself and one.5 is a prime number. It is only evenly divisible by itself and one.
78 is evenly divisible by 1, 2, 3, and 13.
Is 5225 divisible by 3? A number is divisible by 3, if the sum of its digits is evenly divisible by 3. 5 + 2 + 2 + 5 = 14. Since 14 is not divisible by 3, neither is 5225.
No. 108 is composite because it is evenly divisible by 2 and 3, as well as by other products of 2 and 3. In order to be prime, a number must be evenly divisible only by 1 and itself.
It is divisible by any real number. It is divisible evenly by 2, 3, 5 and 419, all prime.
Not evenly. A number is divisible by 3 if the sum of its digits is divisible by 3.