In mathematical terms there is no "wrong" because no rule for generating the sequence has been defined. I can create seven different rules under which one of the given numbers is "wrong".
For example, if t(n) = (n5 - 23n4 + 203n3 - 847n2 + 1698n - 1244)/4 then the first number, 7, is "wrong".
But if t(n) = (n5 - 22n4 + 182n3 - 683n2 + 1170n - 606)/6 then the second number, 13, is "wrong".
It is easy enough to extend this list to the remaining five numbers so that each is "wrong" in the context of one rule or another.
By the above process,
if t(n) = (3n2 + 3n + 8)/2 then the fourth number, 31 is "wrong".
It could be argued that the generating rule is of the polynomial of the lowest order for 31, but that is hardly a good mathematical reason.
The series 112358 represents the Fibonacci sequence, where each number is the sum of the two preceding ones. Following this pattern, the next number after 8 (the last number in the series provided) is 13, as 5 + 8 = 13. Therefore, the next number in the series 112358 is 13.
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17 :)
21. This is the Fibonacci series.
The pattern is - 5 then +2. 2 and 4 are the next numbers in the series.
itz a scrap number
The sequence 14567911 appears to be a series of increasing odd numbers: 1, 5, 7, 9, and then jumps to 11. Following this pattern, the next odd number after 11 is 13. Therefore, the next number in the sequence is 13.
1 - it is the only number that is neither prime nor composite.
It has 13 books because 13 is an unlucky number
To find the next number in the series, we can observe the alternating pattern between pairs of numbers. The first number is 14, and it decreases by 3 to 11, then increases by 7 to 18. Following this pattern, the next number after 18 should decrease by 2, resulting in 16. Therefore, the next number in the series is 16.
To find the total number of combinations using three series of numbers, each ranging from 1 to 13, you multiply the number of choices for each series. Since each series has 13 options, the total combinations are (13 \times 13 \times 13), which equals (13^3 = 2,197). Therefore, there are 2,197 possible combinations.
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