Two and Four are both common denominators of Four and Eight, therefore either of these can be used. You would need only two 4ft square tiles or eight 2ft square tiles to cover the 4ft x 8ft floor.
10,000 of them.
Six (6) sheets exactly cover that area and that shape, without cutting anything.
16 if there is no wastage or cutting.
To determine how many 5-centimeter squares are needed to cover a larger square, you first need to know the dimensions of that larger square. If the side length of the larger square is ( L ) centimeters, then the area of the larger square is ( L^2 ) square centimeters. Each 5-centimeter square has an area of ( 25 ) square centimeters. Therefore, the number of 5-centimeter squares required would be ( \frac{L^2}{25} ), assuming ( L ) is a multiple of 5 to ensure complete coverage without overlapping.
2 x 2 square feet? Do you mean 2 feet x 2 feet? If so, that is 4 square feet and you will need 200 divided by 4 = 50 tiles of 4 sq.ft. That is without wastage or cutting etc.
10,000 of them.
No, you cannot completely cover a 3' x 6' area with 3' x 3' tiles without cutting them. A 3' x 3' tile covers 9 square feet, while the area you want to cover is only 18 square feet. You would need at least two tiles to cover the length, but that would exceed the area dimensions, leaving part of the area uncovered.
It should be obvious that the answer depends on how large the bigger square is.
Six (6) sheets exactly cover that area and that shape, without cutting anything.
Six sheets will exactly cover it, without cutting anything.
16 if there is no wastage or cutting.
Each tile covers a square foot. So you need 542, plus some for spoilage and cutting.
To determine how many 5-centimeter squares are needed to cover a larger square, you first need to know the dimensions of that larger square. If the side length of the larger square is ( L ) centimeters, then the area of the larger square is ( L^2 ) square centimeters. Each 5-centimeter square has an area of ( 25 ) square centimeters. Therefore, the number of 5-centimeter squares required would be ( \frac{L^2}{25} ), assuming ( L ) is a multiple of 5 to ensure complete coverage without overlapping.
tesselation
2 x 2 square feet? Do you mean 2 feet x 2 feet? If so, that is 4 square feet and you will need 200 divided by 4 = 50 tiles of 4 sq.ft. That is without wastage or cutting etc.
The number of 13 inch tiles needed will depend on the actual dimensions of the floor rather than the square footage. If the room is square, 169 tiles, with 1/16 inch or larger grouted seams, will completely cover it. If the floor is rectangular, additional tiles will be needed, the exact number depending on how many tiles must be cut. As a general rule, approximately 10 percent extra is usually sufficient to cover waste from cutting and accidental breakage.
Yes with a trapezoid