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b = 1/2 (a - c)

or for a = 3b - 2c: b = 1/3 (a + 2c)

for a= 2bc + d is b= (a-d)/2c

a= 2b +c is c= a - 2b

b=1/3(a-2c)

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11y ago
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Q: Which of these formulas is correctly rewritten from the original formula to solve for b?
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