2, 8, 16 are factors of 64
6 and 12 are not.
If you mean: 2 6 8 12 and 16 then they are 2 8 and 16
No, 12 is not a divisor of 64. These are 64's divisors: 1, 2, 4, 8, 16, 32, 64.
They are: 1, 2, 4, 8, 16, 32, 64.
Yes, it is.
The greatest common divisor refers to a divisor that is COMMON to two or more numbers. You have only one number in the question! The greatest divisor of any number is itself.
yes
Sixteen is a divisor of 64 because it goes evenly into 64. Here are all of 64's divisors: 1, 2, 4, 8, 16, 32, 64.
1, 2, 4, 8, 16, 32, 64
GCF of two or more numbers can be found using Euclid's Division Lemma.Euclid's Division Lemma: For any two numbers a and b(a>b) we can say a = bq+r.Applying Euclid's Division Lemma to 64 and 12: 64 = 12 x 5 + 4Since the remainder is not equal to zero we apply the division lemma to the divisor 12 and the remainder 4:12 = 4 x 3 + 0The last divisor is 4, which is the GCF(12,64).
Both 16 and 8 are divisors of 64, since both can divide 64 without any remainders. 64/16=4 and 64/8=8.
64 has seven divisors: 1 2 4 8 16 32 64.
64 has these seven divisors: 1, 2, 4, 8, 16, 32, 64.