Which point lies on the line 3x minus 5y 2 6 4 or 4 2 or neg1 1 or 8 14?

Updated: 12/20/2022

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Limit 1 divided by x minus 3 approaches 3 what is the limit?

lim x->3 1/(x-3)First substitute 3 in for x, this gives 1/0 which is undefined and not allowedSo, next set up limits from the left and right sidesFrom the leftlim x->3- 1/(x-3) (the - is the symbol for from the left), this gives 1/a very small neg1/a very small neg= -infinityFrom the rightlim x->3+ 1/(x-3), this gives 1/a very small positive number1/small pos=infinityThe left should equal the right; since it does not, there is an asymptote at x=3

Limit 1 divided by x minus 3 approaches 3 what is the limit?

lim x->3 1/(x-3)First substitute 3 in for x, this gives 1/0 which is undefined and not allowedSo, next set up limits from the left and right sidesFrom the leftlim x->3- 1/(x-3) (the - is the symbol for from the left), this gives 1/a very small neg1/a very small neg= -infinityFrom the rightlim x->3+ 1/(x-3), this gives 1/a very small positive number1/small pos=infinityThe left should equal the right; since it does not, there is an asymptote at x=3

Which point lies on the line 3x minus 5y 2 6 4 or 4 2 or neg1 1 or 8 14?

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Limit 1 divided by x minus 3 approaches 3 what is the limit?

Limit 1 divided by x minus 3 approaches 3 what is the limit?

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