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Which quantity is given by the area under the velocity time graph?
Wiki User
∙ 11y ago
If you're graphing velocity vs. time, you're denoting what velocity you're moving at various points in time.
The slope of the line at any given point is your acceleration at that time.
The area beneath the graph would be the total distance traveled.
For example, if you were traveling at 50mph for one hour, the graph would be a straight line parallel to the x axis. The area will be 1 hour * 50 miles per hour = 50 miles.
By the way, if you can get this concept down, you've figured out the basic ideas of differential and integral calculus! The slope of the graph is the differential, and the area under the curve is the integral.
Wiki User
∙ 14y ago
Wiki User
∙ 11y agoThe quantity measured by the area occupied below a velocity-time graph is displacement. For example, the area of a rectangular shape would be determined by multiplying velocity (m/s) times time (s), which would cancel time and leave meters. The area of a triangular shape would be determined by multiplying velocity (m/s) times time (s) then divide by 2, which again cancels time and leaves meters.
Wiki User
∙ 12y agoThe area under a speed/time graph, between two points in time,
is the distance covered during that time.
Wiki User
∙ 11y agodistance
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Name the two physical quantities which can be obtained from the velocity-time graph?
well, the area under the curve between a time interval is equal to the distance traveled on that specific time interval. So one quantity is distance. As for another quantity, the answer would be velocity, but I think they may want a less obvious answer. A quantity out side of velocity could be instantaneous acceleration. This is given by the slope of the the tangent line to the velocity-time graph. Hope this helps you answer your question. Though I think the most simple way to understanding why is to take a course of calculus.
Area under the velocity time graph line is 40 M. What physical quantity does this area represent?
It represent the distance covered is 40 metre.
How do you go from a position graph to a velocity graph?
you can't....it's merely impossible! Assuming it is a graph of velocity vs time, it's not impossible, it's simple. Average velocity is total distance divided by total time. The total time is the difference between finish and start times, and the distance is the area under the graph between the graph and the time axis.
Name 2 physical quantities that can be obtained from v-t graph?
well, the area under the curve between a time interval is equal to the distance traveled on that specific time interval. So one quantity is distance. As for another quantity, the answer would be velocity, but I think they may want a less obvious answer. A quantity out side of velocity could be instantaneous acceleration. This is given by the slope of the the tangent line to the velocity-time graph.Hope this helps you answer your question. Though I think the most simple way to understanding why is to take a course of calculus.
How do you find the distance from a velocity time graph?
this time is basically the instant when an object has a particular velocity(instantaneous velocity). so on the graph draw a line from the particular value of the velocity and then draw a vertical line on time axis to find the time for that velocity.
What is the unit of a physical quantity which is represented by area under a velocity time graph?
the physical quantity is distance and unit is meters
Name the two physical quantities which can be obtained from the velocity-time graph?
well, the area under the curve between a time interval is equal to the distance traveled on that specific time interval. So one quantity is distance. As for another quantity, the answer would be velocity, but I think they may want a less obvious answer. A quantity out side of velocity could be instantaneous acceleration. This is given by the slope of the the tangent line to the velocity-time graph. Hope this helps you answer your question. Though I think the most simple way to understanding why is to take a course of calculus.
Find position given velocity vs time graph?
postion is the area under the slope
What is the quantity which is measured by the area occupied below the velocity - time graph?
Distance travelled (displacement). Distance = velocity/time, so velocity * time = distance. Likewise, x = dv/dt so the integral of velocity with respect to time (area under the graph) is x, the distance travelled.
Area under the velocity time graph line is 40 M. What physical quantity does this area represent?
It represent the distance covered is 40 metre.
What does the area under an acceleration time graph show?
The area under an acceleration-time graph is equal to the object's velocity (not change in velocity).
How do you go from a position graph to a velocity graph?
you can't....it's merely impossible! Assuming it is a graph of velocity vs time, it's not impossible, it's simple. Average velocity is total distance divided by total time. The total time is the difference between finish and start times, and the distance is the area under the graph between the graph and the time axis.
Which physical quantity is measured by the area under velocity time graph?
The distance covered in the direction of motion or the opposite direction. Distance covered in the transverse direction is not included.
Area under the velocity versus time graph?
Area under velocity versus time graph(between two given instances of time i.e. two points on time axis) gives the displacement of the body( whose graph was plotted) between those two instances i.e. in that time interval. Area under velocity time graph can be found from definite integration if the graph is a curve. Note: Area under velocity versus time graph gives displacement not distance covered by body. Note: Area enclosed between the plotted curve and time axis is taken. For convenience time should be taken in the x-axis.
Name 2 physical quantities that can be obtained from v-t graph?
well, the area under the curve between a time interval is equal to the distance traveled on that specific time interval. So one quantity is distance. As for another quantity, the answer would be velocity, but I think they may want a less obvious answer. A quantity out side of velocity could be instantaneous acceleration. This is given by the slope of the the tangent line to the velocity-time graph.Hope this helps you answer your question. Though I think the most simple way to understanding why is to take a course of calculus.
How do you find the distance from a velocity time graph?
this time is basically the instant when an object has a particular velocity(instantaneous velocity). so on the graph draw a line from the particular value of the velocity and then draw a vertical line on time axis to find the time for that velocity.
What equals the displacement on a velocity-time graph?
Displacement is the area under the v-t graph.
