If you're graphing velocity vs. time, you're denoting what velocity you're moving at various points in time.
The slope of the line at any given point is your acceleration at that time.
The area beneath the graph would be the total distance traveled.
For example, if you were traveling at 50mph for one hour, the graph would be a straight line parallel to the x axis. The area will be 1 hour * 50 miles per hour = 50 miles.
By the way, if you can get this concept down, you've figured out the basic ideas of differential and integral calculus! The slope of the graph is the differential, and the area under the curve is the integral.
well, the area under the curve between a time interval is equal to the distance traveled on that specific time interval. So one quantity is distance. As for another quantity, the answer would be velocity, but I think they may want a less obvious answer. A quantity out side of velocity could be instantaneous acceleration. This is given by the slope of the the tangent line to the velocity-time graph. Hope this helps you answer your question. Though I think the most simple way to understanding why is to take a course of calculus.
It represent the distance covered is 40 metre.
well, the area under the curve between a time interval is equal to the distance traveled on that specific time interval. So one quantity is distance. As for another quantity, the answer would be velocity, but I think they may want a less obvious answer. A quantity out side of velocity could be instantaneous acceleration. This is given by the slope of the the tangent line to the velocity-time graph.Hope this helps you answer your question. Though I think the most simple way to understanding why is to take a course of calculus.
you can't....it's merely impossible! Assuming it is a graph of velocity vs time, it's not impossible, it's simple. Average velocity is total distance divided by total time. The total time is the difference between finish and start times, and the distance is the area under the graph between the graph and the time axis.
A velocity-time graph shows how an object's velocity changes over time. The slope of the graph represents the object's acceleration, and the area under the curve represents the total displacement of the object. It is a useful tool for understanding an object's motion.
well, the area under the curve between a time interval is equal to the distance traveled on that specific time interval. So one quantity is distance. As for another quantity, the answer would be velocity, but I think they may want a less obvious answer. A quantity out side of velocity could be instantaneous acceleration. This is given by the slope of the the tangent line to the velocity-time graph. Hope this helps you answer your question. Though I think the most simple way to understanding why is to take a course of calculus.
the physical quantity is distance and unit is meters
To determine velocity from an acceleration-time graph, you can find the area under the curve of the graph. This area represents the change in velocity over time. By calculating this area, you can determine the velocity at any given point on the graph.
The distance covered in the direction of motion or the opposite direction. Distance covered in the transverse direction is not included.
Distance travelled (displacement). Distance = velocity/time, so velocity * time = distance. Likewise, x = dv/dt so the integral of velocity with respect to time (area under the graph) is x, the distance travelled.
It represent the distance covered is 40 metre.
To find the position from a velocity-vs-time graph, you need to calculate the area under the velocity curve. If the velocity is constant, the position can be found by multiplying the velocity by the time. If the velocity is changing, you need to calculate the area under the curve using calculus to determine the position.
well, the area under the curve between a time interval is equal to the distance traveled on that specific time interval. So one quantity is distance. As for another quantity, the answer would be velocity, but I think they may want a less obvious answer. A quantity out side of velocity could be instantaneous acceleration. This is given by the slope of the the tangent line to the velocity-time graph.Hope this helps you answer your question. Though I think the most simple way to understanding why is to take a course of calculus.
you can't....it's merely impossible! Assuming it is a graph of velocity vs time, it's not impossible, it's simple. Average velocity is total distance divided by total time. The total time is the difference between finish and start times, and the distance is the area under the graph between the graph and the time axis.
The area under an acceleration-time graph is equal to the object's velocity (not change in velocity).
A velocity-time graph shows how an object's velocity changes over time. The slope of the graph represents the object's acceleration, and the area under the curve represents the total displacement of the object. It is a useful tool for understanding an object's motion.
To determine an object's position from a velocity graph, you can find the area under the velocity curve. The area represents the displacement or change in position of the object. The position at any given time can be calculated by adding up the areas under the curve up to that time.