Any REGULAR polygon with 4n (where n = 1, 2, 3, ...) sides eg a square, octagon, dodecagon, etc.
1440 degrees
remember this formula for the number of sides = n sum of internal angles of a regular polygon = [2x(n-2)x90 degree] each interior angle of a regular polygon = [2x(n-2)x90 degree]/n each exterior angle of a regular polygon = 360 degree/n for your question: each exterior angle of a 15 sided regular polygon = 360 degree/15 = 24 degree
5 degrees.
The sum of angles of a regular polygon in degrees = 180(n - 2), where n is the number of sides of the regular polygon. So, where n = 8 the sum of angles in degree = 180(8 - 2) = 180(6) = 1,080 Angle in degree = (The sum of angles in degree)/n Angle in degree = (1,080)/8 = 135 Thus, in a regular octagon, the degree of an angle is 135.
If the 135-degree polygon is a regular polygon and each interior angle measures 135 degrees then the polygon is an eight-sided octagon
Each exterior angle is 72 degrees
That depends whether the 47 degrees is an internal angle or not. Internally, the minimum angle for a regular polygon would be 60 degrees - as in an equilateral triangle.
15
There is no such polygon but if you meant an interior angle of 165 then it will have 360/15 = 24 sides
hextogonImproved Answer:-A regular pentagon which has 5 sides
If you mean the exterior angle of 1 degree then it will have 360 sides.
No regular polygon can have an interior angle of 180 degrees or more. No regular polygon can have an interior angle of 180 degrees or more. No regular polygon can have an interior angle of 180 degrees or more. No regular polygon can have an interior angle of 180 degrees or more.