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Which smallest number when divided by 2 3 4 5 6 7 8 9 and 10 leaves 1 2 3 4 5 6 7 8 and 9 as remainders respectively?
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Related Questions
What is the smallest number which leaves remainders 2 and 12 when divided by 16 and 18 respectively?
66 66/16 = 4 and a remainder of 2 66/18 = 3 and a remainder of 12
What is the smallest number that leaves a remainder 8 12 when divided by 28 32 respectively?
36 divided by 28 would be 1 remainder 8and44 divided by 32 would be 1 remainder 12
What is the smallest number that leaves a remainder 2 when divided by 3 and 4 and 5 and 6?
62 is the smallest number that leaves a remainder of 2 when divided by 3, 4, 5, and 6.
What is the least number which when divided by 52 leaves 33 as the reminder and when divided by 78 leaves 59 and when divided by 117 leaves 98 as the respective reminder then what is the number?
449 is the smallest number that satisfies those requirements.
What are the even whole numbers?
They are the whole numbers that when divided by 2 leaves no remainders
Find the smallest number which leaves a remainder of 3 when divided by 12 and leaves a remainder of 6 when divided by15?
12*1 + 3 = 15 12*2 + 3 = 27 12*4 + 3 = 51 when 51 divided by 15 gives the remainder as 6.
What is the smallest number which when divided by 17 or 29 leaves a remainder of 3?
L.C.M of 17 and 29 is 493.493 + 3 = 496Answer = 496
What do you notice about remainders when prime number are divided by 6?
If the primes are 5 or greater, then the remainders are 1 or 5.This is so trivially obvious.The remainder cannot be 0 or else the number is divisible by 6 and so not a prime.The remainder cannot be 2 or 4 or else the number is divisible by 2 and so not a prime.The remainder cannot be 3 or else the number is divisible by 3 and so not a prime.That just leaves 1 and 5: 11 leaves a remainder of 5, 13 leaves 1 for example.
When a number is divided by 51 it leaves a remainder 40and find the remainder when the same number is divided by17?
6If a divisor of 51 leaves a quotient of 40, the dividend was 2040.If 2040 is divided by 17, the quotient left is 120.From superscot85: All very interesting but nothing to do with the question, which was about remainders, not quotients.Any number which leaves 40 on division by 51 must leave a remainder of 6 on division by 17, as 51 is 3 x 17 and 40 is (2 x 17) + 6.
My house number is the lowest on the street that When divided by 1 2 3 4 5 or 6 leaves a remainder of 1 and when divided by 11 leaves no remainders?
LCM of 1 - 6 is 60 so 61 would leave a remainder of 1, but doesn't divide by 11. Try other multiples of 60 and add 1: 120 + 1 = 121 which is an exact multiple of 11, and there you have it!
What is the least no when divided by 7 and 8 and 9 respectively leaves remainder 2 and 4and 9 respictively?
No answer is possible as any number divided by 9 must either be exactly divisible by 9 or leave a remainder less than 9.
What is the smallest number that leaves a remainder of 7 when divided by 8 and a remainder of 8 when divided by 9?
71 : Python code that demonstrates this. N = 1 while True : if N % 8 8 : print N break N += 1
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