66 66/16 = 4 and a remainder of 2 66/18 = 3 and a remainder of 12
62 is the smallest number that leaves a remainder of 2 when divided by 3, 4, 5, and 6.
121.
No answer is possible as any number divided by 9 must either be exactly divisible by 9 or leave a remainder less than 9.
A number leaves reminder 6 when divided by 10. What is the remainder when the number is divided by 5? Justify your reasoning.
64 and 76
66 66/16 = 4 and a remainder of 2 66/18 = 3 and a remainder of 12
62 is the smallest number that leaves a remainder of 2 when divided by 3, 4, 5, and 6.
6172839
23
0.25
Try 30
85
12*1 + 3 = 15 12*2 + 3 = 27 12*4 + 3 = 51 when 51 divided by 15 gives the remainder as 6.
234568
41
The smallest whole number that can be divided by both 3 and 6 and leaves a remainder of 1 is 7.