C
4 carbons is where you get the "but" (butane). the three "C's" next to each other (in answer C) tells me that it has a triple bond, which is the Alkyne functional group. Alkyne's end with "-yne".
At least that's what I think, hopefully someone smart will come along and properly explain it, I'm just now learning it and so to my limited knowledge, I do believe it's C.
Buthane is a saturated hydrocarbon. That means all the bonds found in this molecule are single covalent bond. Its formula is C4H10. It is the fourth member of the alkane siri.
There 4 isomers : 1) H2C=CHCH2CH3 => but-1-ene 2) CH3CH=CHCH3 => but-2-ene 3) (CH3)2C=CHCH3 => 2- methylpropene 4) CH2-CH2-CH2-CH2 => cyclobutane/cycloalkane. C4h8 has 3 isomers from the same homologous series and one that is not from the same homologous series.
There are at least 5 CH3OCH2CH2CH2CH2CH3 methoxy pentane CH3CH2OCH2CH2CH2CH3 ethoxy butane CH3CH2CH2OCH2CH2CH3 propoxy propane CH3CH(CH3)O(CH3)CHCH3 diisopropyl ether CH3CH2CH2O(CH3)CHCH3 propyl isopropyl ether + CH3OCH2CH2CH2CH2CH3 methoxy pentane with isomers of the pentane chain CH3CH2OCH2CH2CH2CH3 ethoxy butane with isomers of the butane chain
It is a hydrocarbon with the formula, C4H10
Lancelord Kgomokhumo The answer is HYDROCHLORIC ACID.
The formula looks like trans- 2-butene. The c atoms working left to right will have sp3 sp2 sp2, sp3 hybridisation. the bond angles will be tetrahedral on the sp3 centers, 120 0 on the sp2 centres which have a planar shape, with all four substituents lying in the same plane. Good picture in wikipedia. The actual bond angles will deviate slightly.
Butadiene is H2C=C=CHCH3 ; This is one possible isomer. There are 11 covlanet bonds. H2C ' 2 C=C ' 2 C=C ' 2 CHCH3 ' 2 CH3 ' 3 So 2 + 2 + 2+ 2 + 3 = 11
do you go to mvcc
When an alkene of 4 or more carbon atoms is treated with H+, isomerization may occur by migration of the C=C bond along the carbon chain. A strong base such as potassium amide, KNH2, can also promote double bond isomerization. The acid or base acts as a catalyst, i.e. the reactions are acid-catalysed or base-catalysed isomerizations. The C=C bond moves to a more substituted position within the carbon chain, for example but-1-ene isomerizes to but-2-ene in the presence of H+ CH3CH2CH=CH2 (H+catalyst)= CH3CH=CHCH3
1-dehydrohalogenation of n-propylbromide which gives the propene. CH3-CH2-CH2-Br + KOH(Alcoholic) -----> CH3-CH=CH2 2-again hydrohalogenation with HBr gives mostly iso-propylbromide,(Markonikov's rule). CH3-CH=CH2 + HBr ------> CH3-CHBr-CH3 3-The reaction of iso-propylbromide with Sodium metal in presence of anhydrous ether (Wurtz reaction) gives the 2,3-dimethylbutane. 2(CH3-CHBr-CH3) + 2Na ---anhydrous ether--->CH3-CHCH3-CHCH3-CH3
It tell you that is contains 4 carbons (from the "-but" prefix) and it has 1 double bond (from the "ene") and that this double bond is located at the #2 carbon (from the 2). So, it looks like this:CH3CH=CHCH3
The carbon of the carbon-carbon double bond is sp2hybridized. Take CH3CH=CHCH3 as an example: the C of the double bond is sp2 hybridized, cause the C has 3 bond pairs (2 single bonds+1 double bond).The hybridization state of a carbon can be calculated by spn-1 ,where n is the no. of bond pair , and n is stand for a single bond or a double bond or a lone pair electrons.Take CH2=NH as an example: both the N and the C is sp2 hybridized cause for the N, it has one single bond, one double bond and a pair of lone pair electrons.