Since T=2pi*sqrt(l/g) and l is the only variable that effects T that is the period it is the length.
Height does not affect the period of a pendulum.
The period of the pendulum can be influenced by the local magnitude of gravity, by the length of the string, and by the density of the material in the swinging rod (which influences the effective length).It's not affected by the weight of the bob, or by how far you pull it to the side before you let it go.
no ,because they are not the same
The period of a simple pendulum swinging at a small angle is approximately 2*pi*Sqrt(L/g), where L is the length of the pendulum, and g is acceleration due to gravity. Since gravity on the moon is approximately 1/6 of Earth's gravity, the period of a pendulum on the moon with the same length will be approximately 2.45 times of the same pendulum on the Earth (that's square root of 6).
Yes. Given a constant for gravity, the period of the pendulum is a function of it's length to the center of mass. In a higher gravity, the period would be shorter for the same length of pendulum.
The period or frequency of the pendulum
Height does not affect the period of a pendulum.
The weight of the 'bob' doesn't, as long as the distance fromthe pivot to the swinging center of mass doesn't change.
The period of the pendulum can be influenced by the local magnitude of gravity, by the length of the string, and by the density of the material in the swinging rod (which influences the effective length).It's not affected by the weight of the bob, or by how far you pull it to the side before you let it go.
The practical related to pendulum, where we have to calculate it's time period... A pendulum swings...
Its length.
The period increases as the square root of the length.
no it doesnt affect the period of pendulum. the formulea that we know for simple pendulum is T = 2pie root (L/g)
If you'll do some careful measurements, you'll find that it doesn't happen that way.The period of a pendulum depends on its length, but not on how far you pull it to start it swinging.
The period of the pendulum is dependent on the length of the pendulum to the center of mass, and independent from the actual mass.The weight, or mass of the pendulum is only related to momentum, but not speed.Ignoring wind resistance, the speed of the fall of objects is dependent on the acceleration factor due to gravity, 9.8 m/s/s which is independent of the actual weight of the objects.
no ,because they are not the same
The period of a simple pendulum swinging at a small angle is approximately 2*pi*Sqrt(L/g), where L is the length of the pendulum, and g is acceleration due to gravity. Since gravity on the moon is approximately 1/6 of Earth's gravity, the period of a pendulum on the moon with the same length will be approximately 2.45 times of the same pendulum on the Earth (that's square root of 6).