I bet there are millions more out there who share the same, but for two that I know, it's Chris Rock and Ashton Kutcher on February 7.
twins
If they are related then they are twins?
They share a birthday, but not a birth date.
The two celebrities that look alike are America Ferrera and Jordin Sparks.
You may look up your birthday and then a list of celebrities. There are two links attached. They overlap, but do not use exactly the same databases.
On average, in the entire world about twenty eight thousand people will have the same birthday as one another. In a room full of people, there should be two people who have the same birthday.
For the chance to be at least 50% that two people share the same birthday, there needs to be 22 people. For the chance to be exactly 100% that two people share the same birthday, there needs to be 366 people. If there was 365 people, there would be a very small chance that each person in the room would have different birthdays. With 366 people, there are not enough individual days for every person to have a different birthday, so there has to be at least one pair.
No, there are 6 billion people in the world. So the chances of two people being born on the same day are extremely likely. But there is no word for it. It's just, well, not even a covincidence because it's so likely. With 6 billion people in the world, and only 365 days in the year, on average there are more than 16 million people who were born on any particular day.
The two areas that share the same latitude are land and sea.
The probability that 25 random people don't ALL share the same birthday is: 1 - (1/365)**24, or about 0.999999999999999999999999999999999999999999999999999999999999968 However, I suspect you meant to ask "What is the probability that 25 random people all have different birthdays?" That is: 1 * (364/365) * (363/365) * (362/365) * ... * (342/365) * (341/365) = 0.4313 So about 43% of the time nobody will share a birthday, and 57% of the time, two or more people will share a birthday.
23. The probability that at least two people in a room share a birthday can be expressed more simply, mathematically, as 1 minus the probability that nobody in the room shares a birthday.Imagine a fairly simple example of a room with only three people. The probability that any two share a birthday is :1 - [ 365/365 x 364/365 x 363/365]i.e. 1-P(none of them share a birthday)=1 - [ (365x364x363) / 3653 ]=0.8%Similarly,P(any two share a birthday in a room of 4 people)= 1 - [ 365x364x363x362 / 3654 ] = 1.6%If you keep following that logic eventually you getP(any two share a birthday in a room of 23 people)=1 - [(365x364x...x344x343) / 36523 ] = 51%
Yes, they can share the same main drain.