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Q: Who discovered formula of the area of the triangle?

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HERON discovered the area of a triangle in terms of its sides. Heron's formula = [s(s-a)(s-b)(s-c)]1/2Here, s = semiperimeter of a triangle a, b, c = three sides of the triangle

The formula of the area of a triangle is Base * Height / 2

Area of Equilateral Triangle A= S2 * (Root 3)/4, where A= Area of the triangle S= Side of the triangle.

Area of a triangle= half of the base multiplied by the height. A = 1/2 (b) (h) <--formula

Area of a triangle = 0.5*base*perpendicular height Area of a parallelogram = base*perpendicular height

The title of the formula is "Formula for the Area of a Triangle". No discrimination is expressed or implied.

The are of any triangle is calculated by the formula: Area = 1/2 x Base x Height

Area of triangle * 2 + perimeter of triangle * length.

the formula for the area of a triangle is: base times height divided by two.

Area of triangle * 2 + perimeter of triangle * length.

A=bxh

The area of any triangle is1/2 of (the length of the triangle's base) times (the triangle's height).

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