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A sum is the total of all the numbers in the list. To find the sum, add all of the numbers. For example 2+4+8+10=24. 24 is the sum.
AVG is short hand for average. An average is typically found by taking the sum of all the data and then dividing by the number of items in that list. So using our previous example, you would take our sum 24 and divide it by 4 because there were four different numbers. The average would be 8.
Range is the difference between the biggest number and the smallest number. So you would take 10 - 2 and your range would be 8.
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Is a sum of averages accurate?
No, a sum of averages is NOT as accurate as the average of the whole. For example: A=avg (1,10) = 5.5 B=avg (1, 1, 1, 1, 1) = 1 avg(A,B) = 3.25 [Average of averages] avg(1,1,1,1,1,1,10) = 2.29 [The original data set]
Write a program to compute the average of the squares of the numbers from 1 to 10?
main() { sum=0; float avg=0.0; int sqr[10]; for(i=1;i<=10;i++) { sqr[i]=(i*i); } for(i=1;i<=10;i++) { sum=sum+sqr[i]; } avg=sum/10; dts it !!!
What is the algorithm of the program to find sum and average of n different numbers?
1. start 2. sum=0 3. input n 3. for i=1 to n do 4. input x 5. sum=sum+x end of for (3) 6. avg=sum/n 7. output sum, avg 8. stop
C program to calculate sum and average of 4 numbers?
/*mycfiles.wordpress.com To Calculate Sum & Average of 4 no.*/ #include<stdio.h> #include<conio.h> void main() { float a,b,c,d,sum,avg; clrscr(); printf("Enter the 4 nos.\n\n"); scanf("%f%f%f%f",&a,&b,&c,&d); sum=a+b+c+d; avg=(a+b+c+d)/4; printf("\nSum is= %f\nAverage is= %f",sum,avg); getch(); }
How do you find the sum and average of two integers?
Add the numbers together (sum) and divide by two (average). SUM: 2 + 8 = 10 AVG: 10 / 2 = 5
Is a sum of averages accurate?
No, a sum of averages is NOT as accurate as the average of the whole. For example: A=avg (1,10) = 5.5 B=avg (1, 1, 1, 1, 1) = 1 avg(A,B) = 3.25 [Average of averages] avg(1,1,1,1,1,1,10) = 2.29 [The original data set]
C plus plus program for find a sum and avg of given no's?
#include <iostream> using namespace std; int main() { double num[100], avg, sum=0; int i, n; cout<<"Enter amount of numbers "; cin>>n; for(i=0;i<n;i++){ //This for loop adds the numbers as they are entered cout<<"Enter a number: "; cin>>num[i]; sum+=num[i]; } avg=sum/n; cout<<endl<<"The sum is "<<sum<<endl; cout<<"The average is "<<avg; system("pause"); return 0; }
How do you write a java program to find the sum and average score of three marks scored by ten students?
import java.io.*; class summ { public static void main()throws IOException { BufferedReader in=new BufferedReader(new InputStreamReader(System.in)); int a[]=new int[10]; int sum=0; float avg=0; for(int i=0;i<10;i++) { System.out.println("Enter marks of student "+(i+1)+" : "); a[i]=Integer.parseInt(in.readLine()); sum+=a[i]; avg=sum; } avg/=10; System.out.print("Sum= "+sum+"\nAverage= "+avg); } }
Write a program to compute the average of the squares of the numbers from 1 to 10?
main() { sum=0; float avg=0.0; int sqr[10]; for(i=1;i<=10;i++) { sqr[i]=(i*i); } for(i=1;i<=10;i++) { sum=sum+sqr[i]; } avg=sum/10; dts it !!!
WAP to print sum and average of multiples of 5 from 500 to 600?
public class Test { public static void main(String[] args){ int i = 500; int sum = 0; int avg = 0; int counter = 0; do { i = i + 5; sum = sum + i; counter = counter + 1; } while (i
Write a C programme to find out sum of the array elements?
main(){int n,a[i],s;s=0;printf("enter no of elements in array");scanf("%d",&n);printf("Enter elements in array");for(i=;i
What is the algorithm of the program to find sum and average of n different numbers?
1. start 2. sum=0 3. input n 3. for i=1 to n do 4. input x 5. sum=sum+x end of for (3) 6. avg=sum/n 7. output sum, avg 8. stop
How do you use avg?
avg has a wide range of uses thats y is so easy o use
Design a flow chart that will compute the average of 5 numbers?
start input a,b,c,d,e sum=a+b+c+d+e avg=sum/5 print"average is"; avg
C program to calculate sum and average of 4 numbers?
/*mycfiles.wordpress.com To Calculate Sum & Average of 4 no.*/ #include<stdio.h> #include<conio.h> void main() { float a,b,c,d,sum,avg; clrscr(); printf("Enter the 4 nos.\n\n"); scanf("%f%f%f%f",&a,&b,&c,&d); sum=a+b+c+d; avg=(a+b+c+d)/4; printf("\nSum is= %f\nAverage is= %f",sum,avg); getch(); }
How do you find the sum and average of two integers?
Add the numbers together (sum) and divide by two (average). SUM: 2 + 8 = 10 AVG: 10 / 2 = 5
Avg range of rbc for women?
4.2 to 5.4 million/uL
