The two resonance configuration is equally probable in benzene. i.e. all the c-c bonds have 50% probability of single bond and double bond. As a result all the bonds become equal.
The cation formed upon addition of an electrophile to benzene is highly stabilized by resonance,whereas the cation formed to an alkene is stabilized by hyperconjugation. The loss of a proton in benzene is favourable due to the restoration of the cyclic pi-system.
i think the question is wrong.benzene doesn't respond nucleophilic substitution respond electrophilic substitution it is electrophilic then due to resonance there is a partial double bond between carbon of benzene and halogens.so halobenzenes are chemically inert towards electrophilic substitution.
NO!! Oxygen-Carbon Bond in phenol has double bond character in it due to resonance, which is hard to break.
Yes, in phenyl hydrazine the electron pair on terminal nitrogen is always available for attack while in analine the electron pair of nitrogen is less available due to involvement in resonance process with benzene ring.
In the phenoxide ion the charge is delocalized by the resonance in the benzene ring. There is no such delocalization in the ethoxide ion.
The cation formed upon addition of an electrophile to benzene is highly stabilized by resonance,whereas the cation formed to an alkene is stabilized by hyperconjugation. The loss of a proton in benzene is favourable due to the restoration of the cyclic pi-system.
All c-c bond distances are in same due to resonance.
rigid because of the resonance stabilization of the amide (peptide) bond and the C=O (C double bond O) cause the structure to be planar and is therefore incapable of rotation.
i think the question is wrong.benzene doesn't respond nucleophilic substitution respond electrophilic substitution it is electrophilic then due to resonance there is a partial double bond between carbon of benzene and halogens.so halobenzenes are chemically inert towards electrophilic substitution.
NO!! Oxygen-Carbon Bond in phenol has double bond character in it due to resonance, which is hard to break.
The benzene molecule is unsaturated but the double bonds present inside the benzene ring are delocalized due to bond resonance (pi structure). This makes the double bonds of benzene much less reactive then more discreet double bonds (as in ethylene). This structure makes it behave more like a saturated compound, preferring substitution reactions over addition reactions. It is resistant to addition reactions across the double bond because such a reaction reduces the resonance stabilization energy. However, when reactions do occur, resonance stability is almost always re-established (Birch Reduction reactions are exceptions. See related link).
There isn't such a thing as more aromatic. Something is aromatic or not. If you are referring to the stabilization due to aromaticity, naphthalene has more electrons in the stabilizing Pi-system is therefore more stabilized.
sp^2 Due to 3 pi bonds, In reality a single pi 'cloud' of 6 delocalised electrons exists around the ring (refer to resonance structure).
When frequency of a vibrating body becomes equal to its natural frequency the body starts vibrating vigorously due to resonance.
Benzene does not undergo these reaction due to the aromaticity of the ring. The conjugated, cyclic double bond system provides about 38 kcal/mol of stabilization to the molecule. For addition to occur, it would have to disrupt the aromatic nature of the ring and this is very difficult.
NO3- has three resonance structure. One double bond between N and O and another two N - O single bond. Since the double bond can be formed between N and any other O it is said that it has a resonance structure. This means that the true structure of NO3- is not any of this structure, but rather a hybrid of all three. Hence all 3 bond lengths would be identical AND shorter than single bond as it is basically an average between single and double bond. It is of course longer than a double bond
pyridine is less reactive than benzene because when we form its conjugate base then it'll b more stable than dat of benzene.. so more stabler means less reactive.......and also due to more resonance in benzene it will b more reactive...same 4 furan and pyrrole