Because, light is transmitted by the lens
An image formed by a convex lens is described by the lens equation 1/u+1/v=1/f, where u is the distance of the object from the lens, v is the mage distance from lens and f is the focal length of the mirror. The question states that f=10cm and u=15cm, This can be substituted in the lens equation as follows: 1/15+1/v=1/10 1/v =1/30 V=+30 Magnification =v/u =30/15=2. The positive sign of v means the image is real, inverted and it on the opposite side of the object. Solution: The image is twice the same size as the object, real, inverted and on the opposite of the object.
Decrease The Length of The Radius
By reducing its radius or diameter.
That depends: * On the size of the 3D object * On the size of the cubes
it is a heavy line that defines the shape and size of an object in a blueprint
convex lens at 2c
The lens is convex (curved outward). Light entering the lens from the outside is refracted (bent) as it travels through it. This brings the image to a single (focal) point. The distance between the lens and the back of the camera is such that it allows a small image of the photographed scene to be visible (the picture). The image is inverted because of the refraction of light through the lens.
As an object moves closer to a concave lens, the virtual image, that is created on the same side of the lens as the object, will remain upright but will be reduced in size.
This is possible only with a convex lens but with a condition that the object has to be placed in between the optic centre and principal focus of the lens.
There is a relationship between the power of an objective lens and its field of view. As the power of the objective lens increases, the size of its field of view decreases
The image becomes blurred and it's size increases.
SMALLER
LARGER!!
t78tt
Using the expression v/u = Image size / object size we can find the value of v. v = 15 * 3.5/13 = 4 (nearly) So approximately at a distance of 4 mm in front of the lens the image is located on the same side of the object.
Place an object between a magnifying lens and its focal point. The image is right side up and larger than the object
Well it doesn't actually, I assume mean the appearance of size. If so it's due to the curvature of the lens the light reflects off the lens differently causing the light to bend and make said object appear smaller.