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Because, light is transmitted by the lens

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Q: Why do lens flip and decrease the size of the object?
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If the image produced by a lens is the same size as the object then the lens must be?

convex lens at 2c


Why does the lens flip and decrease the size of the picture in a camera?

The lens is convex (curved outward). Light entering the lens from the outside is refracted (bent) as it travels through it. This brings the image to a single (focal) point. The distance between the lens and the back of the camera is such that it allows a small image of the photographed scene to be visible (the picture). The image is inverted because of the refraction of light through the lens.


What happens to an object if you move it closer to a concave lens?

As an object moves closer to a concave lens, the virtual image, that is created on the same side of the lens as the object, will remain upright but will be reduced in size.


What type of lens will produce a virtual image longer in size that of object?

This is possible only with a convex lens but with a condition that the object has to be placed in between the optic centre and principal focus of the lens.


Why does the field of view decrease as the power of objective lens increase?

There is a relationship between the power of an objective lens and its field of view. As the power of the objective lens increases, the size of its field of view decreases


What happens to the image formed by convex lens if the object is moved closer to the lens?

The image becomes blurred and it's size increases.


Compared to its actual size how will an object seen through a concave lens appear?

SMALLER


Compared to its actual size how will an object seen through a convex lens appear?

LARGER!!


What is the focal length of a converging lens which produces a virtual image four time the size of the object the image being 15 cm from the lens?

t78tt


An object is located 15millimeters from a diverging lens the object has a height of 13 mm and the image height is 3.5 mm how far in front of the lens is the image located?

Using the expression v/u = Image size / object size we can find the value of v. v = 15 * 3.5/13 = 4 (nearly) So approximately at a distance of 4 mm in front of the lens the image is located on the same side of the object.


Place an object between a magnifying lens and its focal point the image is?

Place an object between a magnifying lens and its focal point. The image is right side up and larger than the object


How does lens reduce the size of objects?

Well it doesn't actually, I assume mean the appearance of size. If so it's due to the curvature of the lens the light reflects off the lens differently causing the light to bend and make said object appear smaller.