An image formed by a convex lens is described by the lens equation 1/u+1/v=1/f, where u is the distance of the object from the lens, v is the mage distance from lens and f is the focal length of the mirror. The question states that f=10cm and u=15cm, This can be substituted in the lens equation as follows: 1/15+1/v=1/10 1/v =1/30 V=+30 Magnification =v/u =30/15=2. The positive sign of v means the image is real, inverted and it on the opposite side of the object. Solution: The image is twice the same size as the object, real, inverted and on the opposite of the object.
Decrease The Length of The Radius
By reducing its radius or diameter.
That depends: * On the size of the 3D object * On the size of the cubes
size
If the object is moved closer to a convex lens, the image distance will decrease and the image will move closer to the lens. The image size may increase depending on the object distance and object size relative to the focal length of the lens.
The size of the image is based on the distance between the object and the lens, as well as the focal length of the lens. The image can be the same size as the object if the object is at the focal point and the lens follows the 1/f = 1/do + 1/di equation.
A concave lens will produce a virtual image longer in size than the object. This occurs when the object is located between the lens and its focal point. The virtual image will appear on the same side as the object and will be larger in size.
The location and size of the image produced by a converging lens are determined by the object distance and the focal length of the lens. The image is formed on the opposite side of the lens as the object when the object is beyond the focal point (real image), and the size of the image depends on the object distance and focal length according to the lens formula.
The lens is convex (curved outward). Light entering the lens from the outside is refracted (bent) as it travels through it. This brings the image to a single (focal) point. The distance between the lens and the back of the camera is such that it allows a small image of the photographed scene to be visible (the picture). The image is inverted because of the refraction of light through the lens.
A diverging lens. In this case, the object distance will be equal to the image distance but with opposite sign.
A virtual image of an object through a concave lens is always upright, reduced in size, and appears on the same side of the lens as the object. Its location depends on the distance of the object from the lens and the focal length of the lens.
Moving the object away from the lens increases the object-image distance. According to the thin lens equation, as the object-image distance increases, the image distance increases incrementally more than the object distance. This results in a smaller image size due to the inverse relationship between image size and image distance.
A convex lens can form a real or virtual image, depending on the location of the object relative to the lens. It can also magnify or reduce the size of an object depending on the object's distance from the lens.
The distance from a converging lens to the object is called the object distance. It is denoted by the symbol "u" and is measured along the principal axis of the lens. The object distance affects the size and location of the image formed by the lens.
As an object moves closer to a convex lens, the size of the image increases. The orientation of the image remains the same, which means it is still upright if the object is upright and inverted if the object is inverted.
An object seen through a concave lens will appear smaller than its actual size. This is because a concave lens diverges light rays, causing them to spread out, which creates a reduced image size.