Your question is in regard to the "Friedel-Crafts Alkylation" reaction, which is probably the most common way to add an alkyl group to a benzene ring. The reaction is carried out with benzene or a substituted benzene, an alkyl chloride or bromide, and a small amount of a Lewis acid catalyst; usually either FeCl3 or AlCl3 when an alkyl chloride is the reagent, or FeBr3 or AlBr3 when an alkyl bromide is the reagent.
The first step in the reaction forms a carbocation when the halide on the alkyl group is removed by the Lewis acid. If 1-chloropropane is used, the first step of the reaction is:
H3C-CH2-CH2Cl + FeCl3 ''Ä¢√á H3C-CH2-C+H2 + Fe{Cl}4-
Primary carbocations are the least stable ones after the methyl carbocation, therefore they will almost always rearrange if possible to yield a secondary or sometimes even a tertiary carbocation. Thus, the next thing to occur is formation of a secondary carbocation. This happens when a hydrogen atom on the middle carbon migrates to the carbon bearing the positive charge and brings two electrons with it. This is called a hydride shift because the hydride ion is H-, and it takes place as shown:
H H
| '§µ |
H3C-CH-C+H2 ''Ä¢√á H3C-C+-CH3
(I apologize, but these were the best graphics I could do given the tools available here.) The equilibrium shown is in much greater favor of the secondary carbocation, however I would not be surprised if some propyl benzene is formed.
So, there are two parts to the answer to your question: 1) A primary carbocation is formed when a 1-chloro-n-alkane reacts with a strong Lewis acid. 2) Because the reaction of a carbocation with benzene is slower than formation of the primary carbocation, the primary carbocation has time to undergo a hydride shift, thereby creating a much higher concentration of the more stable isopropyl carbocation.
P.S.: Have you studied which groups activate a benzene ring and which groups deactivate the ring, and which groups direct subsequently added groups to the meta position and which groups direct groups later added to the ortho and para positions? If you have, what compound would you expect to be the major product of the reaction? What can one do practically speaking when performing the reaction above to minimize multiple alkylations?
I'm correcting two molecular drawings included in the original posting. They did not come out anywhere close to how they appeared on the screen when I wrote the first answer.
The first one didn't come out that badly:
+
H3C-CH2-CH3 -----> H3C-CH2-CH2 + Fe(Cl)4-.
The second graphic was a drawing of the secondary (isopropyl) carbocation:
+
H3C-CH-CH3. (The "+" symbol is normally drawn much closer to the atom bearing the formal positive charge. It was not possible to do this here as answers rarely require graphics.)
It is because the carbocation formed (primary) is less stable than the secondary carbocation. So that's why.
The problem with isopropyl is the when it dries on the skin it evaporates nutrients in the skin also. i wouldn't recommend it.
Benzene has the structure C6H6 so should have double bonds but it does not instead it has a unsaturated electron above or below it. This is also known as an area of high electron density.
Depends on what you are trying to dissolve. Some other industrial solvents include isopropyl alcohol, methanol, toluene, acetone and methyl ethyl ketone.
You get very cold isopropyl alcohol, about -110 F. Some people call this poor man's liquid nitrogen as it can be used to freeze items just like liquid nitrogen. WARNING: Do not use rubbing alcohol as it contains a large amount of water. Use extreme care when handling super cooled alcohol as it will stick to your skin like wax instead of beading off like liquid nitrogen. Please use appropriate safety gear when performing any science experiment.
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The problem with isopropyl is the when it dries on the skin it evaporates nutrients in the skin also. i wouldn't recommend it.
Add isopropyl alchol
Because all the six positions of benzene are equivalent due to pi electronic cloud (instead of isolated pi bonds).
Rubbing alcohol is 70% isopropyl alcohol, so you wouldn't use it since it contains some water. Use 99% isopropyl alcohol instead.
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2Methyl-1-propanol is isobutanol...I dont know for what purpose you want to replace this with isoproponol.
Benzene has the structure C6H6 so should have double bonds but it does not instead it has a unsaturated electron above or below it. This is also known as an area of high electron density.
Neither. Isopropyl is a particular grouping of atoms ... three carbon atoms in a line, with a bond connecting the middle one to something else. (If the bond connecting it to something else is on one of the end carbons, it's a propyl group rather than an isopropyl group.) All extra valences are filled with hydrogen atoms, so the overall empirical formula for an isopropyl group is C3H7, though remember that the one unfilled valence that's connecting the group to something else is on the middle carbon, so you'll sometimes see it written as (CH3)2CH- instead.
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Depends on what you are trying to dissolve. Some other industrial solvents include isopropyl alcohol, methanol, toluene, acetone and methyl ethyl ketone.
First of all a cycloalkene could be many things, such as, cyclopentane, cyclohexane or like. If you mean the difference between cyclohexene and benzene, then there is the double bound, 3 of a kind in a benzene molecule.
NO,,use Octane booster instead,,adding a lot alcohol will clean out the fuel system so much that might plug up the filter and pump.