Q: Why do you graph x then y but not for slope intercept form?

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The graph of an equation can have a slope and an intercept. Sadly, "x-y-1" is not an equation, so it doesn't have any.

y=mx+b is slope-intercept form y - y1 = m(x - x1) is point-slope form Used in algebra based math. On a graph; m is the slope b is the y-intercept x and y represent points

To graph an equation that is not in slope-intercept form, you can use the process of finding points on the graph and plotting them. Choose a few x-values, plug them into the equation to find the corresponding y-values, and plot those points on the graph. Then, connect the points with a smooth line to complete the graph.

If you have anything that you're planning to graph, it's got to be an equation that has 'x' and 'y' in it. If you have an equation that has 'x' and 'y' in it and you're planning to graph the equation, then you've had enough elementary algebra to know how to solve the equation for 'y'. Do that first and bada bing, it'll be in slope/intercept form.

Intercept for a straight line graph. y = mx + b, where y is the y coordinate, m is the slope, x is the x coordinate, and b is the y-intercept.

Related questions

The graph of an equation can have a slope and an intercept. Sadly, "x-y-1" is not an equation, so it doesn't have any.

y=mx+b is slope-intercept form y - y1 = m(x - x1) is point-slope form Used in algebra based math. On a graph; m is the slope b is the y-intercept x and y represent points

The x-intercept is the point where the graph touches the x-axis.

To graph an equation that is not in slope-intercept form, you can use the process of finding points on the graph and plotting them. Choose a few x-values, plug them into the equation to find the corresponding y-values, and plot those points on the graph. Then, connect the points with a smooth line to complete the graph.

If you have anything that you're planning to graph, it's got to be an equation that has 'x' and 'y' in it. If you have an equation that has 'x' and 'y' in it and you're planning to graph the equation, then you've had enough elementary algebra to know how to solve the equation for 'y'. Do that first and bada bing, it'll be in slope/intercept form.

Intercept for a straight line graph. y = mx + b, where y is the y coordinate, m is the slope, x is the x coordinate, and b is the y-intercept.

y=mx+b Y being the y coordinate M being the slope X being the x coordinate b being the y intercept on the graph

A vertical line on a graph has infinite slope and no y-intercept. Its equation is [ x = a number ]. The number is the line's x-intercept.

Remember the standard form of an equation:Y = (slope) x + (y-intercept)Now take your equationY = (-1) x + (0)Compare yours to the standard one.That's how to find them.Now can you identify the slope and y-intercept of the graph of your equation ?

2y = 5x - 10Putting into Slope-Intercept form, we have y = 5/2 x - 5. So, the y-intercept is -5 and the slope is 5/2 or 2.5. (x-intercept is 2).

If you mean: x+y = 90 then y = -x+90 which is in slope intercept form

y=mx+b in slope intercept form m=slope b=y-intercept