The graph of an equation can have a slope and an intercept. Sadly, "x-y-1" is not an equation, so it doesn't have any.
y=mx+b is slope-intercept form y - y1 = m(x - x1) is point-slope form Used in algebra based math. On a graph; m is the slope b is the y-intercept x and y represent points
To graph an equation that is not in slope-intercept form, you can use the process of finding points on the graph and plotting them. Choose a few x-values, plug them into the equation to find the corresponding y-values, and plot those points on the graph. Then, connect the points with a smooth line to complete the graph.
Intercept for a straight line graph. y = mx + b, where y is the y coordinate, m is the slope, x is the x coordinate, and b is the y-intercept.
If you have anything that you're planning to graph, it's got to be an equation that has 'x' and 'y' in it. If you have an equation that has 'x' and 'y' in it and you're planning to graph the equation, then you've had enough elementary algebra to know how to solve the equation for 'y'. Do that first and bada bing, it'll be in slope/intercept form.
The graph of an equation can have a slope and an intercept. Sadly, "x-y-1" is not an equation, so it doesn't have any.
y=mx+b is slope-intercept form y - y1 = m(x - x1) is point-slope form Used in algebra based math. On a graph; m is the slope b is the y-intercept x and y represent points
The x-intercept is the point where the graph touches the x-axis.
To graph an equation that is not in slope-intercept form, you can use the process of finding points on the graph and plotting them. Choose a few x-values, plug them into the equation to find the corresponding y-values, and plot those points on the graph. Then, connect the points with a smooth line to complete the graph.
Intercept for a straight line graph. y = mx + b, where y is the y coordinate, m is the slope, x is the x coordinate, and b is the y-intercept.
If you have anything that you're planning to graph, it's got to be an equation that has 'x' and 'y' in it. If you have an equation that has 'x' and 'y' in it and you're planning to graph the equation, then you've had enough elementary algebra to know how to solve the equation for 'y'. Do that first and bada bing, it'll be in slope/intercept form.
y=mx+b Y being the y coordinate M being the slope X being the x coordinate b being the y intercept on the graph
A vertical line on a graph has infinite slope and no y-intercept. Its equation is [ x = a number ]. The number is the line's x-intercept.
To graph the equation y-x=3, first rearrange it in slope-intercept form by isolating y: y=x+3. This equation represents a line with a slope of 1 and y-intercept of 3. You can plot the y-intercept at (0,3) then use the slope to find another point and draw a straight line connecting the two points.
Remember the standard form of an equation:Y = (slope) x + (y-intercept)Now take your equationY = (-1) x + (0)Compare yours to the standard one.That's how to find them.Now can you identify the slope and y-intercept of the graph of your equation ?
2y = 5x - 10Putting into Slope-Intercept form, we have y = 5/2 x - 5. So, the y-intercept is -5 and the slope is 5/2 or 2.5. (x-intercept is 2).
If you mean: x+y = 90 then y = -x+90 which is in slope intercept form