The multiplication rule of thumb always states that a negative number times a negative number results in a positive number.
Since an even number is always divisible by two, any value raised to an even integer power will result in a positive number.
However, a basic proof is presented as follows:
(-A) * (-A) = A^2
((-A) * (-A)) ^ 2 = ((-A * -A) * (-A * -A)) = A^2 * A^2 = A ^ 4
No. A negative integer raised to the third power will yield a negative number that is less than the integer. Only whole numbers (positive integers greater than or equal to 1) have the property where that integer raised to the third power is greater than or equal to the integer.
A positive number times a positive number is always positive. A negative number times a negative number is always positive. Therefore, any square number will be positive. Any number to the fourth power (a square times a square) will always be positive. And so on.
-32 this is like saying (-3)(-3) and a double negative is positive -34 this is like saying (-3)(-3)(-3)(-3) since there is two double negatives it is still positive -36 this is like saying (-3)(-3)(-3)(-3)(-3)(-3) since there is three double negatives it is still positive -38 this is like saying (-3)(-3)(-3)(-3)(-3)(-3)(-3)(-3) since there is four double negatives it is still positive This can apply for any negative integer.
It is always negative when raised to an odd power and always positive when raised to an even power -2 to the third power = -2 x -2 x -2 = -8 -2 to the fourth power = -2 x -2 x -2 x -2 = +16
The answer is negative (-1 raised to the power of 100 = -1)
When a negative number is raised to an even power the result is a positive number
No, or more accurately "not necessarily".A negative to any even power is positive. -2, -4, -6 etc. are even, so a negative number raised to any of those powers will be positive.However, a negative number raised to an odd negative power (-1, -3, -5 etc.) will be negative.
No. Negative numbers to even powers are positive.
Yes (when the power is a positive integer). It is possible to have powers that are negative, rational, irrational and even complex and there are similar rules for dealing with them.
It is the positive form of the number raised to that power, multpilied by -1 raised to that power.
x raised to a positive power, a is xa where a> 0. If a is an integer then it is equal to x*x*...*x where there are a lots of x.x raised to a negative power is the same as the reciprocal of x raised to the absolute value of the power. Thus, if b < 0 then xb = 1/x-bwhere -b > 0.x raised to rational or irrational powers are defined using the power laws.Another AnswerThe terms 'positive' and 'negative' powercan also be used to describe the direction of energy flow. For example, when a generator supplies energy to the grid, we can say that the direction of that energy and, therefore, the rate at which the energy flows (i.e. power) is positive. However, when the grid supplies energy back to the generator (causing it to 'motor'), then the energy (and, therefore, the power) is negative.
A base raised to a negative power is equal to 1 divided by that base raised to a positive exponent. So 16 raised to (-3/2) is equal to 1/ (16 raised 3/2), or 1/64.
Any number, positive or negative, raised to an even-numbered power, returns a positive number.
yes, but the answer will remain negative. for example, (-2)3 is -8 in order to make a negative number positive, it must be raised to an even power, for example (-2)2 = 4
The units digit of any number is the number in the ones position. For example, the units digit of 123 is 3; 2324 is 4; and 87321 is one. The reason the answer is 5 for 5 raised to any positive integer is because 5 will always be in the units position. For example, 52 = 25; 53 = 125; 54 = 625; and so on.
Any integer raised to the power of zero is 1.
-120= 1 because 1.) any negative number raised to an even power will result in a positive numberand 2.) 1 raised to any power is 1.
You can understand this by using one rule of exponents. For integers m,n, and positive integer a a^m/a^n=a^(m-n) So if we look at a^m/a^m which must be 1 since it is something divided by itself, we know from the rule we can also write this as a^(n-n)=a^0 but we just showed that was 1.
Yes. Any multiplication involving an odd number of negative operands will be negative (assuming non-zero operands).
no number can be raised to a power and equal 0 (x^y can never = 0). e is positive (about 2.7) and any positive number can not be raised to a power and equal negative (positive number X positive number = positive number)