3 + h = 3 + 100.25 = 103.25
(2h-3)(h+1) = 0 h = 3/2 or h = -1
15
12 - h = -h + 3 Collect like terms giving 12 - 3 = -h + h ie 9 = 0 Something wrong somewhere!
-1
soot
dicarbon trihydrogen
The empirical mass is C2H3 2 x 12 = 24 3 x 1 = 3 24 + 3 = 27 So divide 27 into 166.01 Hence 162.27 / 27 = 6.01 ~ 6 So multiply each atom in the empirical formula by '6' Hence Empirical C2H3 Molecular C12H18
C4H6. C2H3 gives a molecular mass of 27, 54/27 gives 2. Therefore the molecular formula is twice the empirical formula.
Emperical formula FOR C8H12 is C2H3
H 3 H 3 that is who boo.
3 + h = 3 + 100.25 = 103.25
(2h-3)(h+1) = 0 h = 3/2 or h = -1
You can easily derive it from formula for the derivative of a power, if you remember that the cubic root of x is equal to x1/3. This question asks for the proof of the derivative, not the derivative itself. Using the definition of derivative, lim f(x) as h approaches 0 where f(x) = (f(a+h)-f(a))/h, we get the following: [(a+h)1/3 - a1/3]/h Complete the cube with (a2 + ab + b2) Multiply by [(a+h)2/3 + (a+h)1/3 × a1/3 + a2/3] / [(a+h)2/3 + (a+h)1/3 × a1/3 + a2/3] This completes the cube in the numerator, resulting in the following: (a + h - a) / (h × [(a+h)2/3 + (a+h)1/3 × a1/3 + a2/3]) h / (h × [(a+h)2/3 + (a+h)1/3 × a1/3 + a2/3]) h cancels 1 / [(a+h)2/3 + (a+h)1/3 × a1/3 + a2/3] Now that we have a function that is continuous for all h, we can evaluate the limit by plugging in 0 for h. This gives 1/[a2/3 + a1/3 × a1/3 + a2/3] Simplify a1/3 × a1/3 1/[a2/3 + a2/3 + a2/3] (1/3)a2/3 or (1/3)a-2/3 This agrees with the Power Rule.
15
12 - h = -h + 3 Collect like terms giving 12 - 3 = -h + h ie 9 = 0 Something wrong somewhere!
3/10*h or 0.3*h