3 + h = 3 + 100.25 = 103.25
(2h-3)(h+1) = 0 h = 3/2 or h = -1
15
12 - h = -h + 3 Collect like terms giving 12 - 3 = -h + h ie 9 = 0 Something wrong somewhere!
-1
The chemical name for C2H3 is ethyne, also known as acetylene.
The empirical formula C2H3 has a molecular mass of 27 (C: 12, H: 1). To determine the molecular formula with a molecular mass of 54, the molecular formula would simply be double the empirical formula, so the molecular formula would be C4H6.
The name of C2H3 is ethyne, also known as acetylene. It is a hydrocarbon compound with a triple bond between two carbon atoms, commonly used in welding and cutting torches.
C2H3 is the chemical formula for the molecule known as ethynyl, which is also called acetylene. It is a simple hydrocarbon compound consisting of two carbon atoms and three hydrogen atoms, and is commonly used in welding and as a fuel.
To find the molecular formula, you need to know the empirical formula and the molar mass of the compound. First, calculate the empirical formula mass of C2H3 = 2(12.01) + 3(1.01) = 27.05 g/mol. Then, divide the molar mass by the empirical formula mass to get the ratio of 162.27 g/mol / 27.05 g/mol = 6. Using this ratio, the molecular formula would be C12H18.
The compound C2H3 is ethyne, also known as acetylene. It is a colorless gas with a distinct odor, commonly used in welding and as a raw material in chemical synthesis. Ethyne is highly flammable and can form explosive mixtures with air.
H 3 H 3 that is who boo.
3 + h = 3 + 100.25 = 103.25
You can easily derive it from formula for the derivative of a power, if you remember that the cubic root of x is equal to x1/3. This question asks for the proof of the derivative, not the derivative itself. Using the definition of derivative, lim f(x) as h approaches 0 where f(x) = (f(a+h)-f(a))/h, we get the following: [(a+h)1/3 - a1/3]/h Complete the cube with (a2 + ab + b2) Multiply by [(a+h)2/3 + (a+h)1/3 × a1/3 + a2/3] / [(a+h)2/3 + (a+h)1/3 × a1/3 + a2/3] This completes the cube in the numerator, resulting in the following: (a + h - a) / (h × [(a+h)2/3 + (a+h)1/3 × a1/3 + a2/3]) h / (h × [(a+h)2/3 + (a+h)1/3 × a1/3 + a2/3]) h cancels 1 / [(a+h)2/3 + (a+h)1/3 × a1/3 + a2/3] Now that we have a function that is continuous for all h, we can evaluate the limit by plugging in 0 for h. This gives 1/[a2/3 + a1/3 × a1/3 + a2/3] Simplify a1/3 × a1/3 1/[a2/3 + a2/3 + a2/3] (1/3)a2/3 or (1/3)a-2/3 This agrees with the Power Rule.
(2h-3)(h+1) = 0 h = 3/2 or h = -1
15
12 - h = -h + 3 Collect like terms giving 12 - 3 = -h + h ie 9 = 0 Something wrong somewhere!