Group 1 and 2 elements have 1 and 2 valence electrons respectively. Removal of these electrons will result in stable noble gas electronic configuration. Group 17 and 16 elements have 7 and 6 valence electrons respectively. Addition of 1 or 2 electrons to group 17 and 16 respectively will give them stable noble gas configuration.
Hence these two groups are highly reactive and their elements will combine to form large number of compounds.
Their valance electrons form an octet. Each compound wants to have 8 valence electrons (which forms an octet). Groups 1 and 2 have 1 and 2 valence electrons respectively. 16 and 17 have 6 and 7 respectively. So together, they form 8.
Group 1 and 2 elements have 1 and 2 valence electrons respectively. Removal of these electrons will result in stable noble gas electronic configuration. Group 17 and 16 elements have 7 and 6 valence electrons respectively. Addition of 1 or 2 electrons to group 17 and 16 respectively will give them stable noble gas configuration. Hence these two groups are highly reactive and their elements will combine to form large number of compounds.
4*4=16
16
Group 1 and 2 elements have 1 and 2 valence electrons respectively. Removal of these electrons will result in stable noble gas electronic configuration. Group 17 and 16 elements have 7 and 6 valence electrons respectively. Addition of 1 or 2 electrons to group 17 and 16 respectively will give them stable noble gas configuration. Hence these two groups are highly reactive and their elements will combine to form large number of compounds.
Two nonmetals from group 16, such as oxygen and sulfur, are likely to form covalent compounds rather than ionic compounds due to their tendency to share electrons to achieve a stable octet configuration.
104
6
32 groups
16
4
Well, isn't that a happy little math question! If you have 16 and you want to see how many groups of 8 you can make, you simply divide 16 by 8. And you know what? You can make 2 groups of 8 from 16! Just like that, you've created a beautiful division problem.