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Q: Why is 129 divisible by 3?

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129 is divisible by: 1 3 43 129.

129 is divisible by 1 3 43 and 129.

3 or 129.1, 3, 43, 129

Yes - 129/3 = 43

3.

129 is divisible by: 1, 3, 43, 129.

Yes. 129/43=3

129 is divisible by 3. 1+2+9=12 and 12 is divisible by 3. That is the rule of divisibility by 3.

387 is divisible by: 1 3 9 43 129 and 387.

Yes. 1 + 2 + 9 = 12 12 is divisible by 3. If the sum of the digits of a number are divisible by 3, then the whole number is divisible by 3. 129 is a composite number because it divisible by a factor other than 1 and itself.

Yes By 2 = 129 by 3 = 86

It is composite. It is divisible by 3.

When looking for factors, try out some small numbers, such as 2, 3, 5, 7. In this case, it is quite obvious that 129 is not divisible by 2. But if you continue trying, you see that it IS divisible by 3. Of course, if you divide 129 by 3, you get the other factor.

129.129.129.129.

No.

No.

No.

No. 1,000 is not evenly divisible by 129.

No, it isn't divisible by either

No. All multiples of 6 are even and 129 is odd so it cannot be divisible by 6.

1, 3, 5, 15, 43, 129, 215, 645.

1, 3, 37, 43, 111, 129, 1591, 4773.

No, not evenly.

One way to work it out in your head is to consider than 30 is divisible by 3, so you can ask if 140 is divisible by 30. It's not, since 14 is not divisible by 3. If the number was 129 or 159, both of those are divisible by three since both 12 and 15 are divisible by 3.

129 is divisible by three, hence it is a composite number.