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Q: Why is answer 7 wrong for the square root of 63?

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√63 = 3√7 ≈ 7.9372539331937717715

12 times the square root of 7.

3(square root of) 7

sqrt(63)= sqrt(9) x sqrt(7) = 3sqrt(7) is the answer however, the square root of 63 NOT in radical form is ± 7.937254

5*sqrt(63) = 5*sqrt(9*7) = 5*3*sqrt(7) = 15*sqrt(7) = ~39.686

7

Square root of 7 = 2.645751311

Square root of 2 = 1.414213562... Square root of 7 = 2.645751311... The sum is 4.059964873...

no, 28 has no whole square root; the square root of 49 is 7

Seven.

2

The square root of 28 is the same as the 2 x the square root of 7. 7 is prime, and so the square root of 7 is irrational. Thus the square root of 28 is irrational.

7 times the square root of 7

The square root of -7 is: 2.6457513110645907 i

JACK

No, the square root of 7 is NOT an Integer ...The square root of 7 = 2.64575131106

5 square root 7 because 3 square root of 28 goes from 3 square root of 28 to 3 square root of 7 and 4 which then 4 condenses down to 2 and you add that to 3 then you get 5 square root of 7

It is: the square root of 7 times the square root of 7 = 7

the 4th root of 49 is the square root of the square root of 49 since square root 49 =7 then simplify is square root of 7

4 square root of 7

343 is 7 x 7 x 7. The square root is 18.520259....

the square root of 49 equals 7

The square root of 49 is 7 or -7.

a square root is the number multiplied by itself to obtain the given product. for example the square root of 49 is 7 because 7*7=49

the square root of 3, the square root of 5, the square root of 6, the square root of 7, the square root of 8 etc