Strictly speaking you are not subtracting 4 consecutive numbers because the first two (+1 and -2) are not consecutive.
The result is easy to see algebraically.
Suppose you start with x.
Then you are calculating x - (x+1) - (x+2) - (x+3).
That is, x - x-1 - x-2 - x-3 which simplifies to -2x - 6.
Then taking the common factor, -2, out, you get -2*(x+3)
Clarify. Subtract four consecutive numbers ... from what? It appears you mean something like: 22 - 21 - 20 - 19 And the answer is NOT -44. It is -38 ... negative double of the LOWEST number. If this is what you mean, then you have discovered another rule of mathematics. It will always work. 1001 - 1000 - 999 - 998 = -1996 Exactly the negative double of 998
You get a sequence of doubled triangular numbers. This sequence can also be represented by Un = n*(n + 1), [products of pairs of consecutive integers]
a x 3 = ((a + 4) x 2) + 2 ie 3a = 2a + 8 + 2 so a = 10 and other numbers are 12 & 14.
Three consecutive even numbers can be expressed as (x) + (x + 2) + (x + 4), where x is the least of the three numbers. If these three add to 42 then it can be said that: (x) + (x + 2) + (x + 4) = 42 This leads to: 3x + 6 = 42, which results in 3x = 36. So x = 12. This means that numbers are 12, 12+2, and 12+4. The answer is 12, 14, and 16. To double check, 12 + 14 + 16 = 42.n+(n+2)+(n+4)=423n+6=423n=36n=1212, 14, 16
A double minus becomes a plus as for example -2--5 = 3 but -2-5 = -7
Clarify. Subtract four consecutive numbers ... from what? It appears you mean something like: 22 - 21 - 20 - 19 And the answer is NOT -44. It is -38 ... negative double of the LOWEST number. If this is what you mean, then you have discovered another rule of mathematics. It will always work. 1001 - 1000 - 999 - 998 = -1996 Exactly the negative double of 998
There are infinitely many pair of numbers. Take any two numbers that are coprime. Double both of them. Their GCF is 2.
Leaving aside 2, you will get so-called singly even numbers, those which are divisible by 2 but not by 4. (e.g. 2 + 4 = 6) The sum of consecutive even integers (n) + (n+2) is 2n +2, which is double the intervening odd number (n+1).
The English word with three consecutive double letters is "bookkeeper."
The English word BOOKKEEPING or BOOKKEEPER has three sets of consecutive double letters. SUBBOOKKEEPER is the only word with four sets of consecutive double letters, although these words should be hyphenated.
You get a sequence of doubled triangular numbers. This sequence can also be represented by Un = n*(n + 1), [products of pairs of consecutive integers]
"Near doubles" are 2 consecutive numbers. For example: 2 and 3, 7 and 8, 11 and 12. Therefore, 4 + 5 are near doubles.
buccanneer
bookkeeper
committee
Start with n, then you get; Add 17: n + 17 Double it: 2n + 34 Subtract 4: 2n + 30 Double it: 4n + 60 Add 20: 4n + 80 Divide by 4: n + 20 Subtract 20: n which is where you started.
You get a number that's equal to their sum. The sum is an odd number that's greater than either of them, one greater than double the smaller one, and one less than double the bigger one.